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Lady_Fox [76]
3 years ago
10

The ratio of boys and girls in the school

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0

Answer:

45 students

Step-by-step explanation:

to make sure there are 20 boys you need to multiply 4 by 5

so multiply the 5 by 5 as well

then add what you get!!

Elanso [62]3 years ago
6 0

Answer:

45

Step-by-step explanation:

20 boys= 5 times the ratio

So, 5x5=25

25 girls and 20 boys= 45 students

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Determine if the described set is a subspace. Assume a, b, and c are real numbers. The subset of R3 consisting of vectors of the
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Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

7 0
3 years ago
Guyssssssss help me 10 points!!
zlopas [31]

Answer:

19

Step-by-step explanation:

the side is same as 57

what times 3 is 57?

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8 0
3 years ago
What Is the percent equal to 3/10
lianna [129]
30 %
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6 0
3 years ago
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
What is the area of this composite shape?
NNADVOKAT [17]
Area of rectangle = 6 x 7 = 42
area of triangle = 1/2(3)(6) = 9

area of figure = 42 + 9 = 51

answer
51 <span>in²</span>
7 0
3 years ago
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