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stealth61 [152]
3 years ago
11

Can digital formats hold more data than analog

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer: Yes, Digital formats carry more data per second than analog formats

Explanation: The transmission of data from one area (point A) to another area (point B) is refered to as a signal. This signals can be transmitted from point A to point B through two different medium and formats, namely; analog formats and the digital format.

In the analog format, the data is converted into electrical pulse before it's been sent while in digital, data is been converted into binary format representing two amplitude before been sent. Note that devices or machines are at point b (destination) which will collect this pieces of information an convert them into readable and interpretable sounds or image.

Analog signals are a bit old and there is limitation on the size of data that can be transmitted in this formats.

The digital signal is more modern and it carry more data per second compared to the Analog.

So digital formats can hold more data than the analog.

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A student standardizes a solution of aqueous NaOH against a measured mass of solid potassium hydrogen phthalate. She then uses t
wlad13 [49]

Answer:

(D) Neither I nor II

Explanation:

The reagent potassium hydrogen phthalate is found in pure form and it is not partially hydrated .

The pallet form of NaOH ( solid form )  absorbs carbon dioxide gas from the atmosphere but NaOH in solution form does not absorb carbon dioxide .

Hence option D ) is right choice .

8 0
4 years ago
How many electrons are transferred when magnesium bonds ionically with oxygen
andrew11 [14]

Answer:

2 electrons from magnesium (Mg) is transferred to oxygen (O2) to form Mg2+ and O2-

which combines by strong electrostatic force to form MgO

the equation is

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6 0
3 years ago
A pool is 60.0 m long and 35.0 m wide. How many mL of water are needed to fill the pool to an average depth of 6.35 ft? Enter yo
ra1l [238]

Answer:

4.07 × 10⁹ mL

Explanation:

Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

Depth of water in the pool (D): 6.35 ft

Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

6.35ft \times \frac{1m}{3.28ft} = 1.94m

Step 3: Calculate the volume of water (V)

We will use the following expression.

V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}

Step 4: Convert "V" to mL

We will use the relationship 1 m³ = 10⁶ mL.

4.07 \times 10^{3} m^{3} \times \frac{10^{6}mL }{1m^{3} } = 4.07 \times 10^{9} mL

7 0
3 years ago
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