Question

A pool is 60.0 m long and 35.0 m wide. How many mL of water are needed to fill the pool to an average depth of 6.35 ft? Enter your answer in scientific notation.

Answer 1

Answer:

4.07 × 10⁹ mL

Explanation:

Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

Depth of water in the pool (D): 6.35 ft

Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

$6.35ft \times \frac{1m}{3.28ft} = 1.94m$

Step 3: Calculate the volume of water (V)

We will use the following expression.

$V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}$

Step 4: Convert "V" to mL

We will use the relationship 1 m³ = 10⁶ mL.

$4.07 \times 10^{3} m^{3} \times \frac{10^{6}mL }{1m^{3} } = 4.07 \times 10^{9} mL$