Answer:
<em><u>5.a</u></em>
<em><u>6</u></em><em><u>.</u></em><em><u>d</u></em>
<em><u>7.c</u></em>
Explanation:
<em><u>please</u></em><em><u> </u></em><em><u>click</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>heart</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>rate</u></em><em><u> </u></em><em><u>excellent</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>pa</u></em><em><u> </u></em><em><u>brainleist</u></em><em><u> </u></em><em><u>po</u></em><em><u> </u></em><em><u>please</u></em><em><u> </u></em><em><u>☻</u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☺️</u></em><em><u>❤</u></em><em><u>☻</u></em>
I would put yes as in California the dui is .08 or above
Answer:
253 mmol
Explanation:
The solubility is calculated by the given equation:
S(g) = k P(g)
where k = 1.3 x 10⁻³ mol/L-atm
and P(g) = 0.21 (705 mmHg/760 mmHg/atm) = 0.195 atm
Notice the pressure is converted to atm because Henry´s constant is in units of atmospheres , and also we multiplied by 0.21 oxygen composition.
S(g) = 1.3 x 10⁻³ mol/L-atm x 1000 mmol/mol x 0.195 atm x =253 mmol
Here we did multiply by the factor 1000 mmol/mol since the mmol concentration is required in the answer.
Answer:
10moles of kcl
Explanation:
2
K
C
l
O3 → 2
K
C
l + 3
O
2
Notice that you have a 2
:
3 mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 2/3 times more moles of the latter.
15 mol of O2 * ((2mol of KCLO3)/(3mol of O2))= 15*2/3=10 Mol