Answer:
C.0.28 V
Explanation:
Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:
The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:
Cu²⁺ + 2e⁻ → Cu E° = 0.52V
Ag⁺ + 1e⁻ → Ag E° = 0.80V
As the Cu will be oxidized:
Cu → Cu²⁺ + 2e⁻
The cell potential is:
E°Cell = E°cathode(reduced) - E°cathode(oxidized)
E°cell = 0.80V - (0.52V)
E°cell = 1.32V
Right answer is:
<h3>C.0.28 V
</h3>
<h3 />
The volume of a 14.00g of nitrogen at 5.64atm and 315K is 4.59L.
<h3>How to calculate volume?</h3>
The volume of an ideal gas can be calculated using the following ideal gas equation formula;
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
An ideal gas is a hypothetical gas, whose molecules exhibit no interaction, and undergo elastic collision with each other and with the walls of the container.
The number of moles in 14g of nitrogen can be calculated as follows:
moles = 14g ÷ 14g/mol = 1mol
5.64 × V = 1 × 0.0821 × 315
5.64V = 25.86
V = 25.86 ÷ 5.64
V = 4.59L
Therefore, 4.59L is the volume of the gas
Learn more about volume at: brainly.com/question/12357202
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Answer: Depending on the data and the patterns, sometimes we can see that pattern in a simple tabular presentation of the data. Other times, it helps to visualize the data in a chart, like a time series, line graph, or scatter plot.
Explanation:
1960 5.91
1970 5.59
1980 4.83
1990 4.05
2000 3.31
2010 2.60
Answer:
The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year
Explanation:
Given that the mass of the carbon 14 at the start = 5 gram
At the end of 5,000 years we will have;
Where
A = The amount of carbon 14 left
A₀ = The starting amount of carbon 14
e = Constant = 2.71828
= The half life
t = The time elapsed = 5000 years
λ = 0.693/ = 0.693/5730 = 0.0001209424
Therefore;
A = 5 × e^(-0.0001209424×5000) = 2.7312 grams
Therefore, the amount of carbon 14 decayed in the 5000 years is the difference in mass between the starting amount and the amount left
The amount of carbon 14 decayed = 5 - 2.7312 = 2.2688 grams
The average yearly rate of change of carbon-14 during the first 5000 years is therefore;
2.2688 grams/(5000 years) = 0.0004538 grams per year
The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year.
