Answer:
Phosphorous has the smallest atomic size.
Explanation:
As we know these elements belong to same period means there valence shell is the same. So moving from left to right along the period the shell number remains constant but the number of protons and electrons increases. So, due to increase in number of protons the nuclear charge increases hence attracts the valence electrons more effectively resulting in the decrease of atomic size.
Elements and their atomic radius are as follow,
<span><span>Magnesium 0.160 nm
</span><span>
Aluminium 0.130 nm
</span><span>
Silicon 0.118 nm
</span><span>
Phosphorus <span>0.110 nm</span></span></span>
Element 87 francium have the highest atomic size, so in short the closest element to francium have the high atomic size.
Answer:
Primary active transport
Explanation:
In a cell, the movement of molecules like calcium ions (Ca²⁺), <em>to a region having high solute concentration from a region having low solute concentration, through the cell membrane requires metabolic energy</em> and is known as Primary active transport.
It is given that the concentration of calcium in the cell (0.3%) is greater than the concentration of calcium in the fluid surrounding the cell (0.1%). <em><u>So the calcium ions move into the cell and the cell obtains more calcium. </u></em>
<u>Therefore, the cell obtains more calcium by the process of Primary active transport.</u>
Answer:
n = 1.075 moles
Explanation:
Given that,
Mass of oxygen = 34.4 gram
The molar mass of oxygen gas = 32 g/mol
We need to find the number of moles of oxygen. We know that,
No. of moles = given mass/molar mass
So,
So, there are 1.075 moles in 34.4 g of Oxygen gas.
