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dimulka [17.4K]
3 years ago
10

A bicycle wheel has a diameter of 21 inches. What is circumference of this wheel? what is the radius?

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0
Circumference: 65.94 inches
Radius: 10.5 inches
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Find the difference 5/15=5/? <br><br> 6/24=2/?
elena55 [62]

Answer:

the first one is 15 & the second missing number is 8

multiply 15×5 & divide it by 5 & multiply 24×2 n divide it by 6

6 0
3 years ago
Please help ASAP!!
lord [1]

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7 0
2 years ago
Help me please !!!!!​
s2008m [1.1K]
I think it’s either C or A but more than likely C
4 0
3 years ago
Which expression has a sum of one and two twenty ones?
ivanzaharov [21]
Its A

3/7 + 2/3 = 23/21

and 23/21 as a mixed number is:

1 and 2/21
4 0
2 years ago
Read 2 more answers
The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.
Olin [163]

Answer:

h = 5\ cm

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

h = B-5.

 The area of the triangle is 25 cm²

By definition the area of a triangle is:

A = 0.5Bh

For this triangle we know that A = 25\ cm^2 and h = B-5. We substitute these values in the equation and solve for B.

25 = 0.5B (B-5)

0.5B ^ 2-\frac{5}{2}B-25 = 0

Now we use the quadratic formula to solve the equation.

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

B=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:  a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25

Then:

B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}

B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}

B=\frac{5}{2}\±\frac{15}{2}

The solutions are:

B_1=\frac{5}{2}+\frac{15}{2}=10

B_2=\frac{5}{2}-\frac{15}{2}=-5

For this problem we take the positive solution.

B=10\ cm

Now we substitute the value of B in the equation to find the height h

h = 10-5

h = 5\ cm

6 0
3 years ago
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