All categories

3 years ago

Can things of aluminum have a greater mass than things made of iron?

1 answer:

5 0

Yes, if the object is larger. while a solid block of iron will have a greater mass than a block of aluminum of the same size, a much larger block of aluminum can have greater mass than the smaller block of iron.

You might be interested in

Question 6 of 10

madreJ [45]

Answer:

The answer is "Choice B and Choice C".

Explanation:

In this question, the two features, which make electromagnetic waves effective for interaction, which they don't really need a method of travel of data and move information quite fast. The motion among magnetic and electrical forces is generated by electromagnetic radiation. These waves will spread without the need for a source for their movement, and they have high speed and also the electromagnetic waves it has the same frequency as light.

8 0

3 years ago

A living thing that feeds on Another living thing and may kill it eventually is called

Murljashka [212]

Answer:

(D) parasite........................

3 0

2 years ago

GUYS PLEASE HELP THIS IS DO IN LIKE 30 MIN!!!!!!

Tom [10]

Answer:

1: a all of the above

2: b earth tones

3: b doors

4: c industrial

5: d door levers

6: a walk in shower

7: b cork

8: a basic counter tops that are easily accessible

Explanation:

I took the test and got 100%

5 0

4 years ago

Read 2 more answers

What makes up a compound?

iVinArrow [24]

A
.....................

7 0

3 years ago

Read 2 more answers

Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was

Eduardwww [97]

Answer:

4.18

Explanation:

Givens

The car's initial velocity $v_{i}$ = 0 and covering a distance Δx = 1/4 mi = 402.336 m in a time interval t = 4.43 s.

Knowns

We know that the maximum static friction force is given by:

$f_{s_max} =$ μ_s*n (1)

Where μ_s is the coefficient of static friction and n is the normal force.

Calculations

(a) First, we calculate the acceleration needed to achieve this goal by substituting the given values into a proper kinematic equation as follows:

Δx= $v_{i} +\frac{1}{2} at^2$

a=41 m/s

This is the acceleration provided by the engine. Applying Newton's second law on the car, so in equilibrium, when the car is about to move, we find that:

$f_{y}=n-mg=0\\ n=mg\\f_{x}=F-f_{s,max} =0\\ f_{s,max}=F=ma\\$

Substituting (3) into (1), we get:

$f_{s,max}=$ μ_s*m*g

Equating this equation with (4), we get:

ma= μ_s*m*g

μ_s=a/g

=4.18

3 0

4 years ago