Let F = required force, N
Given:
d = 12 m, distance
W = 280 J, work done
By definition,
W = F*d,
therefore
(F N)*(12 m) = (280 J)
F = 280/12 = 23.33 N
Answer: The force is 23.3 N (nearest tenth)
Distance= speed x time
distance = 2.6 m/s x 120s
distance= 312 meters
Answer:
56327040000 metres
Explanation:
1 mile =
1609.344 metres
35000000 miles = x meters
we represent x by the number of meters which the requested miles maps to
we cross multiply, so 1609.344×35000000 = 1 × x
x =56327040000 metres
(1) You must find the point of equilibrium between the two forces,
<span>G * <span><span><span>MT</span><span>ms / </span></span><span>(R−x)^2 </span></span>= G * <span><span><span>ML</span><span>ms / </span></span><span>x^2
MT / (R-x)^2 = ML / x^2
So,
x = R * sqrt(ML * MT) - ML / (MT - ML)
R = is the distance between Earth and Moon.
</span></span></span>The result should be,
x = 3.83 * 10^7m
from the center of the Moon, and
R - x = 3.46*10^8 m
from the center of the Earth.
(2) As the distance from the center of the Earth is the number we found before,
d = R - x = 3.46*10^8m
The acceleration at this point is
g = G * MT / d^2
g = 3.33*10^-3 m/s^2
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