Answer:
emf induced in the loop, at the instant when 9.0s have passed = 1.576 * 10 ⁻² V.
Direction is counter clockwise.
Explanation:
See attached pictures.
<em><u>Given</u></em><em> </em> :
- <em>O</em><em>bject </em><em>position</em><em> </em>( u ) = - 36 cm
- <em>focal</em><em> </em><em>length</em><em> </em>( f ) = - 16 cm
- <em>image position</em><em> </em>( v ) = ?
now, we know
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<em><u>
</u></em>
So<em><u>, image position</u></em> = 28.8 cm, at same side of object .
Rate of speed, probs is the answer
The potential difference between the plates will be 1552 Volts.
<h3>What is a potential difference?</h3>
Voltage, or the difference in electric potential between two points, is defined as the amount of labor per unit of charge needed to move a test charge between the two points.
Given that a 3.7-f capacitor that stores sufficient energy to operate a 75.0-w
The potential difference will be calculated by the formula below:-
Q = I t
Where I = charge / time
Q = V * C
V C = I t
V = I t / C
V = 75 C/s x 60 sec / 2.9 faraday
V = 1552 Volts
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