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3 years ago

14

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find

all solutions whenever they exist.
X + 3y = 9

3x –y = 7

1 answer:

Blababa [14]3 years ago

4 0

$After\ adding\ equations\ and\ simplifying:\\\\One\ solution:\\\\x=number\\ example: x=2\\\\ infinitely\ many\ solutions:\\\\ Left\ side=\ Right\ side\\ example:\\ 2=2\\\\ No\ solutions:\\\\2 \neq 5$ $\left \{ {{x+3y=9} \atop {3x-y=7}\ \ |*3} \right.\\\\ \left \{ {{x+3y=9} \atop {9x-3y=21}} \right.\\+--------\\\\Addition\ method:\\\\10x=30\ \ |:10 \\\\x=3\\\\x+3y=9\\\\3y =9-x=9-3=6\\\\y=2\\\\ \left \{ {{y=2} \atop {x=3}} \right.$

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Andrews [41]

Answer:

centre = (- 3, - 2) , radius = 1

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

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Given

x² + 6x + y² + 4y + 12 = 0 ( subtract 12 from both sides )

x² + 6x + y² + 4y = - 12

Use the method of completing the square on the x and y terms

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(3)x + 9 + y² + 2(2)y + 4 = - 12 + 9 + 4

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Zinaida [17]

Answer:

The answer is

<h2> $(4 \: , \: - 6)$ </h2>

Step-by-step explanation:

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From the question the points are

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The midpoint is

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We have the final answer as

<h3> $(4 \: , \: - 6)$ </h3>

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