In my number, the digit in the ones place is double the digit in the tens place. The sum of the digits is 3
1 answer:
Answer:
12
Step-by-step explanation:
2, the digit in the ones place is double 1, the digit in the tens place. 2 + 1 = 3.
Hope this helps!
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Answer:
10x+4b+3
Step-by-step explanation:
x+x+x+x+x+x+x+x+x+x+b+b+b+b+3
There are 10 x
4 b
and one number
10x+4b+3
Answer:
Yes
Step-by-step explanation:
they were just dilated differently
I don’t see any question. What is the question.
Answer:
Step-by-step explanation:
The entered points belong to an increasing, linear function.
Equation: y = 1x + 4.

Let's solve for x ~

[ by vertical opposite angle pair ]




Therefore, the correct choice is D. 6