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Mademuasel [1]
4 years ago
6

Find the given limit lim(x,y)→(a,a)x4−y4x2−y2=lim(x,y)→(a,a) (x^4−y^4)/(x2−y2)= here aa is a constant. (find the limit assuming

x≠y)
Mathematics
1 answer:
Aliun [14]4 years ago
7 0
If x\neq y, then we can write

\dfrac{x^4-y^4}{x^2-y^2}=\dfrac{(x^2-y^2)(x^2+y^2)}{x^2-y^2}=x^2+y^2

and since this is continuous for all x\neq y, the limit as (x,y)\to(a,a) will be

\displaystyle\lim_{(x,y)\to(a,a)}\frac{x^4-y^4}{x^2-y^2}=\lim_{(x,y)\to(a,a)}(x^2+y^2)=2a^2
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