What is equivalent to log 25<br> 125

There are approximately 4.3 weeks in each month. How much will you take home each month after taxes?

Marianna [84]

Answer:

So roughly c x c = b/100

5 x 5 x 100 = $2500

Step-by-step explanation:

Lets say c = 5 and b = 1

= 5c =100c/5c x b

= 20c x b

We can also show

= 20c x b =5c

c = 20c/5c x b = 5c

1/20 x 5c = 5c

b=1

One example is 20% = 0.20 x 500 = 100c

= 7.12c = 7c

1= 100%

100 x 71.042 = 710.42 weekly pay. emergency tax 142 = 568

100 x 71.042 = 710.42 weekly pay, normal tax 15% 142.084 =107

710-107 = 603 a week

4.3/7 x 603/7 = 86.1428571429 x 30 = 2584.29

4 0

3 years ago

What is the equation 12= x+ 3

IgorC [24]

X=12 because you would sub the 3 on both sides

3 0

3 years ago

Three students were working on 630,000÷700 in math class.

stealth61 [152]

Step-by-step explanation:

a) Desiree is correct 630000÷70=900

6 0

3 years ago

For the month of November in a certain city, 88% of the days are cloudy. Also in the month of November in the same city, 54%

Gnoma [55]

Answer:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

Step-by-step explanation:

We have these following probabilities:

An 88% probability that the day is cloudy.

An 54% probability that the day is both foggy and cloudy.

What is the probability that a randomly selected day in November will be foggy if it is cloudy?

This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

$P = \frac{0.54}{0.88} = 0.6136$

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

4 0

3 years ago

Which statement is not true for a binomial distribution with n = 15 and p = 1/20 ? a) The standard deviation is 0.8441 b) The nu

malfutka [58]

Answer:

d) The highest probability occurs when x equals 0.7500

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability, given by the following formula:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$n = 15, p = \frac{1}{20}$

a) The standard deviation is 0.8441

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15*0.05*0.95} = 0.8441$

This is correct

b) The number of trials is equal to 15

n is the number of trials and $n = 15$ . So this option is correct.

c) The probability that x equals 1 is 0.3658

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658$

This option is correct.

d) The highest probability occurs when x equals 0.7500

False. The number of sucesses is a discrete number, that is, 0, 1, 2,...,15. P(X = 0.75), for example, does not exist.

e) The mean equals 0.7500

$E(X) = np = 15*0.05 = 0.75$

This option is correct.

f) None of the above

d is false

3 0

3 years ago

What is equivalent to log 25 125