Answer:
The equation of line perpendicular to given line equation and passing through point (4,3) is y = 3 x - 9 .
Step-by-step explanation:
Given as :
The given equation of one line = y = x + 5
∵ Equation of line in slope-intercept form is written as
y = m x + c
where m is the slope of line
And c is the intercept of y
Now, Comparing given line equation with standard slope intercept line equation
∴ m =
Slope of this line = m =
Now, another line is perpendicular to the given line
For perpendicular lines , the products of slope of lines = - 1
Let the slope of another line = M
So, from perpendicular lines condition
m × M = - 1
∴ M =
I.e M =
So, M = 3
∴ The slope of other line = M = 3 , and the line passing through point (4,3)
Now, Again
The equation of line in slope-intercept form
I.e y = M x + c
Now, satisfying the points on line
So, 3 = 3 × 4 + c
Or, 3 = 12 + c
∴ c = 3 - 12
i.e c = - 9
or, The other line equation = y = 3 x - 9
Hence, The equation of line perpendicular to given line equation and passing through point (4,3) is y = 3 x - 9 . Answer
