10) through: (3.-1). slope = -1
1 answer:
Answer:
Step-by-step explanation:
The question is to find the equation of the line going through the points (3,-1) and has a slope of -1.
First, the equation of a line is given as:
Equation = y = mx + b
Where
m is the slope
b is the y-intercept (y-axis cutting point)
We know the slope, so the equation becomes:
y = mx + b
y = -1x + b
y = -x + b
Now the point given is in the form (x,y), so
x = 3
y = -1
We substitute and find b:
y = -x + b
-1 = -3 + b
-1 + 3 = b
b = 2
Final Equation:
y = -x + 2
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Answer:
There are no solutions for the pair of equations.
The lines are parallel to each other
Step-by-step explanation:
Line Q has a slope of 1/2 and crosses the y axis at 3.
This mean at x=0, y=3
Using the equation of a straight line expression to find the slope
y=mx +c where m is slope and c in the y intercept you can write the equation for Line Q as;
For the Line S , slope is 1/2 and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c
The equation for S will be
Using the graphing tool to plot the two equations for line Q and line S we notice that the lines are parallel .For solutions, they have to intersect.
