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riadik2000 [5.3K]
3 years ago
9

What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12? (–∞, –3] [–3, ∞) (–∞, 15] [15, ∞)

Mathematics
1 answer:
kvasek [131]3 years ago
8 0

-3(6- 2x) \geq4x + 12\\\\-18+6x\geq4x+12\\\\2x\geq30\\\\x\geq15\\\\x\in[15,\infty)

So, the last one.

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Probability of three chip being defective is 0.012

Step-by-step explanation:

Probability of a computer chip being defective is 0.08 or 8%

Total random sample = 20

Probability of three chip being defective = 3/20 * 0.08

= 0.012

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The perimeter of a square is 36 inches. Find the length to f one side.
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9  because 36 divided by 4 is 9

Step-by-step explanation:

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The cost of turkey is directly proportional to its weight. If a 12-pound turkey costs $27, how much does a 16-pound turkey cost?
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D

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This is for number 10

6 0
3 years ago
The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th
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Answer:

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C

Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

Differentiate both sides with respect to t

6x^5\,dx=dt

[use (x^n)'=nx^{n-1}]

So,

∫6x^5(x^6-2)\,dx = ∫ t\,dt = \frac{t^2}{2}+C_1 where C_1 is a variable.

(Use ∫t^n\,dt=\frac{t^{n+1} }{n+1} )

Put t=x^6-2

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1

Use (a-b)^2=a^2+b^2-2ab

So,

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

where C=2+C_1

Without using substitution:

∫6x^5(x^6-2)\,dx = ∫6x^{11}-12x^5\,dx = \frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C

So, same answer is obtained in both the cases.

7 0
3 years ago
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