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Nikitich [7]
3 years ago
6

In a certain population, 10% of the people can be classified as being high risk for a heart attack. a) Three people are randomly

selected from this population. What is the probability that exactly one of the three are high risk
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer: 0.243.

Step-by-step explanation:

The probability in this case is approcimated by the probability distribution formula for random variables. This formula is denoted as:

P(X=r) = nCr * p^r * q^n-r

Where n = selected number to be sampled and in this case, n= 3

r = varied number of sample and in this case, r=1

P = probability of success and in this case p = 0.10

q = 1-p=1-0.1 = 0.9

P(X=1) = 3C1 × 0.1¹ × 0.9²

P(X=1) = 0.243.

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Answer:

Step-by-step explanation:

Show that if 3x – 7 = 5, then x = 4.

Here, our given statement is 3x – 7 = 5, and we're asked to prove x = 4.

x=4

Statements Reasons

1. 3x – 7 = 5 Given

2. 3x – 7 + 7 = 5 + 7 Addition of 7 to equation (1)

3. 3x + 0 = 5 + 7 Substitution of –7 + 7 = 0 into (2)

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Step-by-step explanation:

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3 years ago
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