The for this problem would be C, 50
Answer:
by using goog_le, or by asking a teacher
Answer:
Expected winnings for one spin = 0.1
Step-by-step explanation:
Expected Value = Sum of [(Probability of X)(Value of X)]
E(X) = Σ [P(X).X]
Two Events : X = +68 , P(X) = 1/38 and X = -2 , P(X) = 37/38
E(X) = [(68) (1/38)] + [(-2)(37/38)]
[(68)(0.03)] + [(-2)(0.97)]
= 2.04 - 1.94
= 0.1
Answer:
Step-by-step explanation:
Formula to be used is N=N0e^(kt)
N0 - amount of bacteria at time 0, which is 10g
t=2, 30g
30 = 10*e^(k*2)
3 = e^(2k)
2k = ln3
k = 0.5ln3
At t=6:
N = 10*e^(0.5ln3*6)
N = 10e^(3ln3)
N = 10e^ln27
N = 10*27 =270
So the amount of bacteria at t=6 is 270
Your answer would like be 5 5/8
