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2 years ago

The factorization of 150 is ?

Mathematics

1 answer:

hram777 [196]2 years ago

6 0

150
/ \
2 75
/ \
3 25
/ \
5 5

so <span> factorization is 2*3*</span> $5^{2}$

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If I have right angle triangle with a hypotenuse of 12meters and an angle of 60degrees what is the length

ad-work [718]

There are 2 basic trangles used in SAT,
45-45-90
30-60-90

if you look in the attachment you will know the relationship between each so

with a 30-60-90 triangle which you have
hypotonuse=2x
hypotonuse=12
2x=12
divide by 2
x=6

I'm not sure about the length, but I'm assuming you mean the longer side

the measure of each leg is 6 and 6 times√3

the lonnger one is 6√3
the answer is 6√3 meters

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2 years ago

Is the algebra 1 regents hard?

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Not if you know your mathmatics

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3 years ago

Yeast , a key ingredient bread , thrives within the temperature range of 90° F to 95°F . Write and graph an inequality that repr

NeX [460]

Answer:

Please find attached the required graph of the inequality representing the temperatures yeast will NOT thrive

Step-by-step explanation:

The given parameters are;

The temperature range, y, in which yeast thrives is 90°F ≤ y ≤ 95°F

Therefore, the temperature range, y', in which yeast will not thrive is 90°F > y and y > 95°F

The graph of the inequality that represents the temperature is therefore given as shown in the attached drawing.

7 0

2 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

2 years ago

Find x in the given triangle

nordsb [41]

X = 19
Because it’s an isosceles triangle, those two sides have to equal to each other so
2x+ 7 = 45
Subtract 7 from both sides
2x = 38
Divide by 2
X = 19

4 0

2 years ago

Read 2 more answers