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boyakko [2]
3 years ago
11

The factorization of 150 is ?

Mathematics
1 answer:
hram777 [196]3 years ago
6 0
150
/  \
2  75
     /  \
    3   25
          /   \
          5   5

so <span> factorization is 2*3*</span>5^{2}

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For the right triangles below, find the values of the side lengths a and h . Round your answers to the nearest tenth.
Strike441 [17]
<h2>H is to 3 and d is to 2 Thats my answer #brainliestbunch - _ - </h2>
7 0
3 years ago
A vehicle with a mass of 500 kg rolls down a slanted road with an acceleration of 0.04 m / s2. The frictional force
lilavasa [31]

Answer:

a) Sketch  in annex

b)  angle is  22 °

c) grade of the hill is  tan 22°  =  0,40

Step-by-step explanation: See Annex for free body diagram

According to Newton´s second law

∑ Fy  =  0      ⇒   mg cos ∠CAB - Fn  = 0

Notice  ∠ CAB  =  ∠ POD  ( They have perpendicular sides )

mg  =  500 Kg * 9.8 m/sec²     ⇒   mg  =   4900 [N]

mg cos ∠CAB - Fn  = 0      ⇒  4900*cos ∠CAB   =  Fn      (1)

∑ Fx  =  ma

mg* sin  ∠CAB  - Fr  =  500* 0.04 m/sec²   =  20 [N]

4900 * sin  ∠CAB   =  1800  + 20  [N]

sin  ∠CAB  = 1820 / 4900   ⇒  sin  ∠CAB  = 0.3714

From tables we get

∠CAB  = 22°

6 0
4 years ago
I can't seem to factor out this equation.<br><br> 40x squared -46x +12
rusak2 [61]
2(5X-2) (4X-3) is the correct answer
5 0
3 years ago
Find the distance between the points (0,0) and(6,-8)
Y_Kistochka [10]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (0, 0) and (6, -8). Substitute:

d=\sqrt{(6-0)^2+(-8-0)^2}=\sqrt{6^2+(-8)^2}=\sqrt{36+64}=\sqrt{100}=\boxed{10}

7 0
4 years ago
The exponential function that models cell duplication in a lab is f(t) = 2^ t+2 where f(t) is the number of cells after time t (
o-na [289]
ANSWER

11.29 \: hours

EXPLANATION

The exponential function that models cell duplication in the lab is given as

f(t) = {2}^{t + 2}

We want to determine the time it will take for the cells to increase to
10,000.

In other words, we want to find the value of
t
when
f(t) = 10,000

This gives us the equation,

10,000 = {2}^{t + 2}

Recall that,

{a}^{m + n} = {a}^{m} \times {a}^{n}

We apply this property to the right hand side to obtain,

10,000 = {2}^{t} \times {2}^{2}

This implies that,

10,000 =4 \times {2}^{t}

We divide both sides by 4 to get,

2500 = {2}^{t}

We take the antilogarithm of both sides to base 10 to get,

t = log_{2}(2500)

This implies that,

t = 11.29 \: hours
to the nearest hundredth.
6 0
4 years ago
Read 2 more answers
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