The two numbers are 3 and 5, because 3 is the product of 3(1) = 1, and 3(5) = 15. Which is divisible by 5. Both 3 and 5 are less than 10.
The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
For the answer to the question above,
From the data given, generate first the quadratic equation which best describe the height of the ball. The quadratic function has a general form of
f(x) = Ax^2 + Bx
Substituting the known data,
(1) 148 = A(1^2) + B(1)
(2) 272 = A (2^2) + B (2)
solving for A and B simultaneously,
A = -12
B = 160
So the to answer this problem, substitute 6 to x. Thus, after 6 seconds, the height is 528 feet.
Answer:
78ft
Step-by-step explanation:
a^2 + b^2 = c^2
72^2 + 30^2 = 6084
square root 6084 to get 78
Answer:188
Step-by-step explanation:
u have to add all the side which is 46+46+13+13=188
