<h2>
Answer:</h2>
The expression which represents the perimeter P of the rectangle as a function of L is:
<h2>
Step-by-step explanation:</h2>
The length and width of a rectangle are denoted by L and W respectively.
Also the diagonal of a rectangle is: 10 inches.
We know that the diagonal of a rectangle in terms of L and W are given by:
( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )
Hence, we have:
But we know that width can't be negative. It has to be greater than 0.
Hence, we have:
Now, we know that the Perimeter of a rectangle is given by:
Here we have:
Answer:
There are 100 pennies in one dollar.
Step-by-step explanation:
We have two points describing the diameter of a circumference, these are:
Recall that the equation for the standard form of a circle is:
Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.
For this we use the following equation:
Now, we replace and solve:
The center of the circle is (-8,-7), so:
On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:
In this case, we will solve the delta with the center coordinate and the B coordinate.
Therefore, the equation for the standard form of a circle is:
In conclusion, the equation is the following:
The isosceles triangle is missing so i have attached it.
Answer:
Length of unknown side = 5p + 6
Step-by-step explanation:
In isosceles triangle, two of the sides are equal. In the attached triangle, we see that one of the equal sides is given as 5p + 3.
Thus,the second equal side is also 5p + 3.
Now, perimeter of a triangle is the sum of the three sides.
We have two sides and let the third side be denoted as x.
Thus;
Perimeter = (5p + 3) + (5p + 3) + x
We are given perimeter = 15p + 12
Thus;
(5p + 3) + (5p + 3) + x = 15p + 12
10p + 6 + x = 15p + 12
Rearranging, we have;
x = 15p - 10p + 12 - 6
x = 5p + 6
Since there are 14 boys and the whole class has 31 students
We get, the ratio of the part-to-whole relationship for boys is 14/31.
And since there are 17 girls
We get, the ratio of the part-to-whole relationship for girls is 17/31.
