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postnew [5]
3 years ago
12

A square wall is 30 ft ^2. What is the length of one wall?

Mathematics
1 answer:
Serggg [28]3 years ago
8 0
√30 = 5.47722557505

so 5.5ft × 5.5ft  ≈ 30ft²

I hope I helped

ΩΩΩΩΩΩΩΩΩΩ
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ANSWER ASAP GIVING BRAILIEST AND STUFF!
natita [175]

Answer:

24s^2, 54s^2, 96s^2

Step-by-step explanation:

Let s represent the initial side length of the cube.  Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).

a) Now suppose we double the side length.  The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),

b) tripled:  A = 6(3s)^2 = 54x^2

c) quadrupled?  A = 6(4s)^2 = 96s^2

6 0
3 years ago
Under her cell phone plan, Morgan pays a flat cost of $54 per month and $5 per gigabyte, or part of a gigabyte. (For example, if
Bogdan [553]

Answer: She can use 4 gigabyte while remaining in her budget.

Step-by-step explanation:

You would first subtract 54  from 70 which leaves you with 16,

Then you would divide 16 by 4 to find how many gigabytes she could use which gives you 4

So she can use 4 gigabyte while remaining in her budget.

Learn  more about basic mathematics operations here

brainly.com/question/28493322

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7 0
2 years ago
Read 2 more answers
Find such m, that point (-2,4) is on line y=mx-3
Andreas93 [3]

Answer:

-3.5 ( or -7/2)

Step-by-step explanation:

we can substitute the point into this function to find out the answer

that is:

4 = m*(-2) -3

7 = m*(-2)

m = 7 / (-2)

m = -3.5

3 0
2 years ago
Gia is painting her wall. 1 liter of paint can cover 10 square meters. She has a rectangular wall that
garik1379 [7]
5*4 equals 20 so her wall is 20 square meters
Given that one litre can cover 10 square meters, she needs 2 litres of paint to cover the wall
7 0
3 years ago
an angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5cm long. A second side of the
rodikova [14]
There is a not so well-known theorem that solves this problem.

The theorem is stated as follows:
"Each angle bisector of a triangle divides the opposite side into segments proportional in length to the adjacent sides"  (Coxeter & Greitzer)

This means that for a triangle ABC, where angle A has a bisector AD such that D is on the side BC, then 
BD/DC=AB/AC

Here either
BD/DC=6/5=AB/AC, where  AB=6.9,  
then we solve for  AC=AB*5/6=5.75,

or

BD/DC=6/5=AB/AC, where  AC=6.9,  
then we solve for AB=AC*6/5=8.28

Hence, the longest and shortest possible lengths of the third side are
8.28 and 5.75 units respectively.

4 0
3 years ago
Read 2 more answers
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