Can someone help me out

d1i1m1o1n [39]

Answer: No it is not.

Step-by-step explanation: A rational number is a number that can easily be expressed as a fraction or decimal, and square root of 7 cannot be easily expressed.

6 0

2 years ago

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What is the slope between the points 5,-1 and -2,-3?

pishuonlain [190]

To find slope, use the equation (y2-y1)/(x2-x1). In your case, the equation is going to look like (-3 - -1)/(5 - -2) or (-3 +1)/(5 + 2), and that simplifies to -2/7.

8 0

3 years ago

Simultaneous equations 5x+y=28 x+y=2

ludmilkaskok [199]

Answer:

Step-by-step explanation:

$5x + y = 28$

$x + y = 8$

Solve the equation for y by moving 'x' to R.H.S and changing its sign

$5x + y = 28$

$y = 2 - x$

Substitute the given value of y into the equation 5x + y = 28

$5x + 2 - x = 28$

Solve the equation for x

Collect like terms

$4x + 2 = 28$

Move constant to R.H.S and change its sign

$4x = 28 - 2$

Subtract the numbers

$4x = 26$

Divide both sides of the equation by 4

$\frac{4x}{4} = \frac{26}{4}$

Calculate

$x = \frac{26}{4}$

Reduce the numbers with 2

$x = \frac{13}{2}$

Now, substitute the given value of x into the equation y = 2 - x

$y = 2 - \frac{13}{2}$

Solve the equation for y

$y = - \frac{9}{2}$

The possible solution of the system is the ordered pair ( x , y )

-------------------------------------------------------------

Let's check if the given ordered pair is the solution of the system of equation:

plug the value of x and y in both equation

$5 \times \frac{13}{2} - \frac{9}{2} = 28$

$\frac{13}{2} - \frac{9}{2} = 2$

Simplify the equalities

$28 = 28$

$2 = 2$

Since , all of the equalities are true, the ordered pair is the solution of the system.

$(x \:, y \: ) = ( \frac{13}{2} \: , - \frac{9}{2})$

Hope this helps....

Best regards!!

5 0

3 years ago

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Joe won a lottery jackpot that will pay him $12000.00 eachyear

geniusboy [140]

Answer:

$3863.68

Step-by-step explanation:

Please see attachment

4 0

2 years ago

Solve the problem. If s is a distance given by s(t) = + + 40 + 10. find the acceleration, alt). Q ald) = 10 ald) = 2t + 4 O alt)

QveST [7]

Answer:

C

Step-by-step explanation:

Remember that if s(t) is a position function then:

$v(t)=s'(t)$ is the velocity function and

$a(t)=s''(t)$ is the acceleration function.

So, to find the acceleration, we need to solve for the second derivative of our original function. Our original function is:

$s(t)=t^2+4t+10$

So, let's take the first derivative first with respect to t:

$\frac{d}{dt}[s(t)]=\frac{d}{dt}[t^2+4t+10]$

Expand on the right:

$s'(t)=\frac{d}{dt}[t^2]+\frac{d}{dt}[4t]+\frac{d}{dt}[10]$

Use the power rule. Remember that the derivative of a constant is 0. So, our derivative is:

$v(t)=s'(t)=2t+4$

This is also our velocity function.

To find acceleration, we want to second derivative. So, let's take the derivative of both sides again:

$\frac{d}{dt}[s'(t)]=\frac{d}{dt}[2t+4]$

Again, expand the right:

$s''(t)=\frac{d}{dt}[2t]+\frac{d}{dt}[4]$

Power rule. This yields:

$a(t)=s''(t)=2$

So, our answer is C.

And we're done!

6 0

3 years ago