Answer:
¶Emma Jess¶
Step-by-step explanation:
,
UV
1 answer:
You might be interested in
Question has missing figure, the figure is in the attachment.
Answer:
The measure of ∠1 is 65°.
The measure of ∠2 is 65°.
The measure of ∠3 is 50°.
The measure of ∠4 is 115°.
The measure of ∠5 is 65°.
Step-by-step explanation:
Given,
We have an isosceles triangle which we can named it as ΔABC.
In which Length of AB is equal to length of BC.
And also m∠B is equal to m∠C.
ext.m∠C= 115°(Here ext. stands for exterior)
We have to find the measure of angles angles 1 through 5.
Solution,
For ∠1.
∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.
So, we can frame this in equation form as;
On putting the values, we get;
-115\°=65\°[/tex]
Thus the measure of ∠1 is 65°.
For ∠2.
Since the given triangle is an isosceles triangle.
So,
Thus the measure of ∠2 is 65°.
For ∠3.
Here ∠1, ∠2 and ∠3 are the three angles of the triangle.
So we use the angle sum property of triangle, which states that;
"The sum of all the angles of a triangle is equal to 180°".
Now we put the values and get;
Thus the measure of ∠3 is 50°.
For ∠4.
∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.
So, we can frame this in equation form as;
Substituting the values of of angle 2 to find angle 4 we get;
Thus the measure of ∠4 is 115°.
For ∠5.
∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.
So, we can frame this in equation form as;
Substituting the values of of angle 4 to find angle 5 we get;
Thus the measure of ∠5 is 65°.
Hence:
The measure of ∠1 is 65°.
The measure of ∠2 is 65°.
The measure of ∠3 is 50°.
The measure of ∠4 is 115°.
The measure of ∠5 is 65°.
Answer:
183 miles to the nearest mile.
Step-by-step explanation:
Distance =Speed X Time
Distance of Truck B from point A=45 X2 =90 miles
Distance of Truck C from point A=55 X2 =110 miles
Angles between them, BAC=132°
We want to find the Distance BC denoted by a between the trucks.
Using Cosine Rule,
a²=b²+c²-2bcCos A
=90²+110²-(2X90X110XCos132°)
=33448.79
a=√33448.79
BC=182.89 miles
The distance between the trucks is 183 miles to the nearest mile.
