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abruzzese [7]
2 years ago
5

UV

Mathematics
1 answer:
icang [17]2 years ago
8 0
I think the answer would be SSS. but i haven’t done proofs and shi for like 2 years
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\displaystyle\\f(x)=3x^2+1\\g(x)=1-x\\\\(f-g)(x)=f(x)-g(x)=3x^2+1-(1-x)=3x^2+1-1+x=\boxed{3x^2+x}\\\\(f-g)(2)=f(2)-g(2)=3\cdot2^2+2=3\cdot4+2=12+2=\boxed{14}




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