Answer:
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Given :
2.5 mole of Sulfuric acid 
.
To Find :
Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid
Solution :
Let us assume volume of water be 1 L .
Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .
So , for 2.5 mole sulfuric acid required 5 mole of NaOH .
Moles of NaOH ,
Molecular mass of NaOH , M.M = 58.44 g/mol .
Mass of 5 moles of NaOH :
Hence , this is the required solution .
Answer:
- <em>The pH of the solution is </em><u><em>7</em></u>
Explanation:
<em>The pH</em> is a measure of the acidity of the solutions. It is defined as the negative logarithm of the molar concentration of hydrogen ions (H⁺).
<em>The hydrogen ion concentration of this solution is 1 × 10⁻⁷ M.</em>
Hence:
- pH = - log (1 × 10⁻⁷) = - (-7) = 7
This pH corresponds to a neutral solution (neither acid nor alkaline).
You should remember this relation bwtween pH and acidity/alkaliinity:
- Low pH (0.0 or close) corresponds to strong acids
- HIgh pH (14.0 or close) corresponds to strong bases
- Acids have pH between 0.0 and 7.0
- Bases have pH between 7.0 and 14.0
Answer:
Losing 2 valence electrons
Gaining 2 electrons
