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Lelechka [254]
3 years ago
13

Dolomite, [CaMg(CO3)2] is found in a soil sample. A geochemist titrates 24.65 g of soil with 57.85 mL of 0.3315M HCl. What is th

e mass % of dolomite in the soil? ( Write answer to two decimal places, ex. 15.77)
Chemistry
1 answer:
pshichka [43]3 years ago
8 0

In order to find out the %mass dolomite in the soil, calculate for the mass of dolomite using the information given from the titration procedure. You would need to multiply 57.85 ml with 0.3315 M HCl and you would get the amount of HCl in millimoles. Then multiply the amount of HCl with 1/2 (given that for every 1 mol of dolomite, 2 mol of HCl would be needed). Convert the amount of dolomite to mass by multiplying the millimoles with the molecular weight which is 184.399. Then convert the mass to grams which is 1.768 grams. Divide the mass of dolomite (1.768 grams) with the weight of soil sample. The % mass is 7.17. 

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Answer:

The human musculoskeletal system (also known as the locomotor system, and previously the activity system) is an organ system that gives humans the ability to move using their muscular and skeletal systems. The musculoskeletal system provides form, support, stability, and movement to the body.

Explanation:

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The enthalpy of combustion of benzoic acid (C6H5COOH) is commonly used as the standard for calibrating constant-volume bomb calo
Anit [1.1K]
<h3>Answer:</h3>

28.96 kJ/°C

<h3>Explanation:</h3>

We are given;

  • Enthalpy change (ΔH) = −3226.7 kJ/mol
  • The reaction is exothermic since the heat change is negative;
  • Mass of benzoic acid = 3.1007 g
  • Temperature change (21.84°C to 24.67°C) = 2.83°C

We are required to find the heat capacity of benzoic acid;

<h3>Step 1: Moles of benzoic acid </h3>

Moles = Mass ÷ molar mass

Molar mass of benzoic = 122.12 g/mol

Therefore;

Moles = 3.1007 g ÷ 122.12 g/mol

          = 0.0254 moles

<h3>Step 2: Determine the specific heat capacity </h3>

Heat change for 1 mole = 3226.7 kJ

Moles of Benzoic acid = 0.0254 moles

But;

Specific heat capacity × ΔT = Moles × Heat change

  cΔT = nΔH

Therefore;

Specific heat capacity,c = nΔH ÷ ΔT

                                     = (3226.7 kJ × 0.0254 moles) ÷ 2.83°C

                                    = 28.96 kJ/°C

Therefore, the specific heat capacity of benzoic acid is 28.96 kJ/°C

7 0
4 years ago
The volume of a gas is 550 mL at 960 mm Hg and 200.0 C. What volume
Masja [62]

Answer:

The volume will be 568.89 mL.

Explanation:

Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, the pressure of the gas is directly proportional to its temperature. Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T}=k

Where P = pressure, T = temperature, K = Constant

Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T} =k

Studying an initial state 1 and a final state 2, it is fulfilled:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

In this case:

  • P1= 960 mmHg
  • V1= 550 mL
  • T1= 200 C= 473 K (being 0 C=273 K)
  • P2= 830 mmHg
  • V2= ?
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Replacing:

\frac{960 mmHg*550 mL}{473K} =\frac{830 mmHg*V2}{423 K}

Solving:

V2=\frac{423 K}{830 mmHg} *\frac{960 mmHg*550 mL}{473K}

V2= 568.9 mL

<u><em>The volume will be 568.89 mL.</em></u>

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