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Akimi4 [234]
3 years ago
10

In a test of a particular weight loss program, weights of 40 subjects are recorded before and after the program. The before-and-

after weights result in a correlation coefficient of 0.876. Assuming a 0.05 significance level, find the critical values. Is there sufficient evidence to support the claim of a linear correlation between before-and-after weights?
Mathematics
2 answers:
Paraphin [41]3 years ago
4 0

I just took the quiz, the answer is A: Critical values=0.312; there is sufficient evidence to support a claim of a linear correlation between before-and-after weights.

nalin [4]3 years ago
3 0

Answer:

A- 0.312 there is

B - 0.561

D - 0.254

A - 0.917 there is

A - .707 there is NOT

A - 0.918

A - 0.765

B - -0.992

B - 0.985, crit= 0.917

C - 0.867, crit= 0.878

Step-by-step explanation:

just did it

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ind the length of the longest side of the rectangle whose vertices are given. A(2, 1), B(5, 4), C(0, 3), D(3, 6) 2 rad2 3 rad2 r
trasher [3.6K]

Distance between A and B  

= Distance between C and D  

= sqrt((4 - 1)^2 + (5 - 2)^2)  

= sqrt(3^2 + 3^2)  

= sqrt(2 * 3^2)  

= sqrt(3^2) * sqrt(2)  

= 3sqrt(2)  

Distance between B and C  

= Distance between A and D  

= sqrt((4 - 3)^2 + (5 - 0)^2)  

= sqrt(1^2 + 5^2)  

= sqrt(26)  

Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).

Hope this helps you.

5 0
3 years ago
Help fast please I going to fail
Scilla [17]

Answer:

  1. 0.5
  2. 0.25
  3. 0.4
  4. 1.05
  5. 0.05
  6. Hope this helps
4 0
2 years ago
Arrange the parabolas represented by the equations in increasing order with respect to the y-values of their directrixes.
Alexus [3.1K]
(x-h)^2=4P(y-k), vertex is (h,k)
P is distance from vertex to directix
remember to subtract P from the y value of the vertex (p-k) and that y value is the directix, y=p-k

nut
ok so one way is to just graph them on a graphing utility
remember if the graph opens up, then the directix is below that
or we can convert to 4P(y-k)=(x-h)^2 form where P is distance from directix

I will only convert the 1st one fully, you should be able to do the rest

1. y=-x^2+3x+8
multiply both sides by -1 since we don't like the x^2 term negative
-y=x^2-3x-8
add8 to both sides
-y+8=x^2-3x
take 1/2 of linear coeficient and square it and add to both sides
-3/2=-1.5
 (-1.5)^2=2.25
-y+10.25=x^2-3x+2.25
factor perfect square
-y+10.25=(x-1.5)^2
force undistribute -1 in left side
(-1)(y-10.25)=something, we don't care anymore for now
factor out a 4 in -1
4(-1/4)(y-10.25)

k=10.25
p=-1/4=-0.25
directix=k-p=10.25-(-0.25)=10.5
directix is y=10.5

basically completee the square with x and find P by force factoring a 4 out

2.  directix: y=-1.75

3. directix: y=1.5

4. directix: y=17.25

5. d: -37.5

6. d: 9.25

7. d=2.625

order them yourself

7 0
3 years ago
Identify the percent change <br><br> 28 seconds to 23 seconds
Zarrin [17]
Percent change=change/original times 100
chane=28-23=5
oriiginal=28

percent change=5/28 times 100
0.178 times 100
17.8

about 18% change
4 0
3 years ago
The formula F=9/5(K−273.15)+32
Lyrx [107]
Just subtract 32, then divide by 9/5 (or multiply by the reciprical) then add 273.15.
K=5/9(F-32)+273.15
3 0
3 years ago
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