Answer:

Step-by-step explanation:



120,808.8
Not sure if this is right, comment if it’s not
Treat

as the boundary of the region

, where

is the part of the surface

bounded by

. We write

with

.
By Stoke's theorem, the line integral is equivalent to the surface integral over

of the curl of

. We have

so the line integral is equivalent to


where

is a vector-valued function that parameterizes

. In this case, we can take

with

and

. Then

and the integral becomes


<span />
<span>the probability that a pen from the first box is selected
= total number of pens in 1st box/total number of objects in box 1
= 5/12
</span>the probability that a crayon from the second box is selected
= total number of crayons in 2nd box/total number of objects in box 2
= 6/8 = 3/4