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3 years ago

How do you solve 15-2x=3x

Mathematics

2 answers:

sergeinik [125]3 years ago

8 0

HEY There,

15-2x=3x

bring 2x to the right hand side

15 = 3x + 2x

15 = 5x

then, bring 5 to the denominator

15/5 = x

3 = x

HOPE YOU UNDERSTAND!!!!!!!!!!!!!

bekas [8.4K]3 years ago

6 0

3) 15 - 2x = 3x

Add 2x to both sides so only one side contains the variable x.

15 = 5x

Divide both sides by 5.

x = 3; if you want to check your solution then plug x back into the original equation.

15 - 2(3) = 3(3)

15 - 6 = 9 ⇒ 9 = 9 so this would be true, your answer is correct.

____________________________________________________________

15) 10(2y + 2) - y = 2(8y - 8)

Distribute 10 and 2 inside their respective parentheses.

(20y + 20) - y = (16y - 16)

Combine like terms on the left side of the equation.

19y + 20 = 16y - 16

Subtract 16y from both sides.

3y + 20 = -16

Subtract 20 from both sides.

3y = -36

Divide both sides by 3.

y = -12

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Step-by-step explanation:

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2 years ago

What is the quotient?

Ierofanga [76]

Answer:

3/2

Step-by-step explanation:

For dividing rational expressions such as the one given, we use the same concept that we use when dividing fractions.

Thus, we multiply the first expression with the second expression's reciprocal as shown below.

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We can cancel common factors and simplify the product. Hence, we have

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2 years ago

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Setler79 [48]

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3 years ago

100 POINTS!!!!!!!!!!!!!!!!!

vesna_86 [32]

Answer:

A = 0.25*j + 1

Step-by-step explanation:

The question presented here is an application of linear models. The $1 amount is fixed and does not depend on any factor such as the cups of orange juice sold.

Furthermore, we are informed that we earn $0.25 for every cup of orange juice sold. This means that we shall earn 0.25 j by selling j cups of orange juice.

The variable total amount, A will thus depend on the fixed amount of $1 and the variable income 0.25 j.

The equation in two variables that will represent the total amount A (in dollars) you have after selling j cups of orange juice will thus be;

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Hope this helped.....

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3 years ago

Read 2 more answers

Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i

Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a Poisson process at the rate of 5.5 per hour and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

$\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}$

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

$\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558$

(b) What is the probability that at least 4 arrive during a 1-hour period?

$\bf P(X\geq4)=1-P(X$

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

$\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}$

and we want P(X ≥ 75) = 1-P(X<75). But

$\bf P(X$

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0

3 years ago