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nordsb [41]
3 years ago
12

 help :))))))))))))))

Mathematics
2 answers:
matrenka [14]3 years ago
7 0

Answer:

no solution

Step-by-step explanation:

slava [35]3 years ago
3 0

Answer:

-3

Step-by-step explanation:

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PLEASE HELP ASAP!!! What is the standard form for the quadratic function? g(x) = (x + 5)^2 −1
dedylja [7]

Answer:

g(x)= x^2+10x + 24.

Step-by-step explanation:

g(x) = (x + 5)^2 −1

= x^2 + 5x + 5x + 25 - 1

= x^2 + 10x + 24

g(x)= x^2+10x + 24 is your answer.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Show each step to solve the equation below:<br><br> 4x+5=x+2
Eduardwww [97]

4x + 5 = x + 2
Subtract 2 from both sides.

Your equation will be: 4x+3=x
Subtract 4x from both sides.
Yoir equation will be: 3= -3x
Divide by -3x on both sides.

Your final answer: x=-1
5 0
3 years ago
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*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
How do I do the first question and second<br> ?
asambeis [7]

Answer for Problem 2:

x=61 degrees

Step-by-step explanation:

I'm not completely sure of problem 1, but I know what problem 2 is.

Tip:  triangles always add up to 180 degrees.

1. 16+42= 58

2. 180-58= 122

3. 122 divided by 2= 61 degrees

ANSWER: x=61 degrees.

6 0
3 years ago
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Complete this statement: "subtraction is the addition of the...."
tresset_1 [31]

Answer:

Subtraction is the Addition of the opposite of the subtrahend to the minuend.

Step-by-step explanation:

PLS GIVE BRAINLIEST

4 0
2 years ago
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