9514 1404 393
Answer:
- 22 touchdowns
- 13 field goals
Step-by-step explanation:
Let t represent the number of touchdowns scored. Then 35-t is the number of field goals, and the total score is ...
7t +3(35 -t) = 193
4t = 88 . . . . . . . . . . simplify, subtract 105
t = 22
35 -t = 13
The team scored 22 touchdowns and 13 field goals.
Answer/Step-by-step explanation:
5. 21x + 4 = 22x - 2 (corresponding angles)
Collect like terms
21x - 22x = -4 - 2
-x = -6
divide both sides by -1
x = 6
6. (x + 72) + (x + 132) = 180 (linear pair)
x + 72 + x + 132 = 180
Add like terms
2x + 204 = 180
2x = 180 - 204
2x = -24
x = -12
7. 90 = 22x + 2 (vertical angles)
90 - 2 = 22x
88 = 22x
Divide both sides by 22
4 = x
x = 4
8. 12x + 10 = 13x + 3 (vertical angles)
Collect like terms
12x - 13x = -10 + 3
-x = -7
Divide both sides by -1
x = 7
9. 17x = 16x + 5 (alternate exterior angles)
17x - 16x = 5
x = 5
✔️17x
Plug in the value of x
17(5) = 85°
10. 21x - 6 = 20x (corresponding angles)
Add like terms
21x - 20x = 6
x = 6
✔️20x
20(6) = 120°
Answer:
First part representing requirements for the length x>=5 ft
Second part yes
Step-by-step explanation:
Well, the formula for finding the area of a rectangle is l x w. In the question, it states that the pen must be 4 ft wide and to fit his requirements of the pen being at the minimum 20 ft^2 we have this inequality 4x>=20 which we must solve and we get x>=5 which means that this represents all of the possible lengths for the play space. For the second part, we know that to fufill Judah's requirements for square ft., our length must be greater than or equal to 5. Last time I was doing math, I'm pretty sure 5 1/2>5 which thus can be accepted as a length value, still meeting the requirements of at least 20ft^2 space for the play space.
