The given histogram represents <span>the number of hamburgers students ate in a month :
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From the histogram we can conclude the following:
(1) 8 students ate (0 - 4) hamburgers
(2) 3 students ate (5 - 9) <span>hamburgers </span>
(3) 2 students ate (10 - 14) <span>hamburgers
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note: we don't know how many students ate exactly 5 hamburgers.
<span>So, the answer
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The information which is provided in the histogram<span>
</span><span>
</span><span>The number of students who ate 10 hamburgers or more
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The problem is asking how much each person will need to pay. Simplifying the problem into an equation with variables (an algorithm) will greatly help you solve it:
S = Sales Tax = $ 7.18 per any purchase
A = Admission Ticket = $ 22.50 entry price for one person (no tax applied)
F = Food = $ 35.50 purchases for two people
We know the cost for one person was: (22.50) + [(35.50/2) + 7.18] =
$ 47.43 per person. Now we can check each method and see which one is the correct algorithm:
Method A)
[2A + (F + 2S)] / 2 = [ (2)(22.50) + [35.50 + (2)(7.18)] ]/ 2 = $47.43
Method A is the correct answer
Method B)
[(2A + (1/2)F + 2S) /2 = [(2)(22.50) + 35.50(1/2) + (2)7.18] / 2 = $38.55
Wrong answer. This method is incorrect because the tax for both tickets bought are not being used in the equation.
Method C)
[(A + F) / 2 ]+ S = [(22.50 + 35.50) / 2 ] + 7.18 = $35.93
Wrong answer. Incorrect Method. The food cost is being reduced to the cost of one person but admission price is set for two people.
Answer:
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Step-by-step explanation:
Answer:
Selling Price = M.P. – Discount = 100 – 5 = Rs. 95. If S.P. is Rs 95, then M.P. is Rs. 100.
