Solving for y, <span>y=±<span><span>14−2<span>x2</span></span><span>−−−−−−−</span>√</span></span><span>
for y to be a positive integer, (14-2x^2) must be a perfect square.
Any positive integer values chosen for x will not yield a perfect square</span>
Answer:
A (i think)
Step-by-step explanation:
If i'm right please mark me branliest
Answer:
12 possible outcomes.
Sample space:
![\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccc%7D%28F%2C1%29%26%28A%2C1%29%26%28I%2C1%29%26%28R%2C1%29%5C%5C%28F%2C2%29%26%28A%2C2%29%26%28I%2C2%29%26%28R%2C2%29%5C%5C%28F%2C3%26%28A%2C3%29%26%28I%2C3%29%26%28R%2C13%29%5Cend%7Barray%7D)
Step-by-step explanation:
The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.
1. There are four possible outcomes for the first wheel: F, A, I and R
2. There are three possible outcomes for the second wheel: 1, 2 and 3
So, the sample space is
![\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccc%7D%28F%2C1%29%26%28A%2C1%29%26%28I%2C1%29%26%28R%2C1%29%5C%5C%28F%2C2%29%26%28A%2C2%29%26%28I%2C2%29%26%28R%2C2%29%5C%5C%28F%2C3%26%28A%2C3%29%26%28I%2C3%29%26%28R%2C13%29%5Cend%7Barray%7D)
I think the inequality is less than or equal to (here what the sign looks like ≤ )
Answer:
21.875
Step-by-step explanation:
you do 175 divided by 8