The answer would be (0,5)
4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
The answer is d.
Finding area of ABCD :
- Find side length
2. Apply formula to find area
Finding area of GHIA :
Finding area of DEFG :
Now, let's see whether is true.
- Area (ABCD) - Area (GHIA) = Area (DEFG)
- 25 - 16 = 9
- 9 = 9
∴ Hence, it is proved √
Answer:
y=
x+2
Step-by-step explanation:
hope this helps
