Answer:
Okay 2
Step-by-step explanation:
Okay since that is that you gotta that 23u172, got it?
<span>6b^3 (2a+7b)
</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)
</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)
</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]
Answer: </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>
Equivalent expressions are expressions of equal values
The equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6 and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
<h3>How to determine the equivalent expressions</h3>
The first expression has been solved.
So, we have the following expressions
4x−7y−5z+6 and -3x−8y−4−87z
<u>4x−7y−5z+6</u>
We have:
4x-7y-5z+6
Rewrite as:
4x+ (y - 8y) + (2z-5z) +6
<u>-3x−8y−4−87z</u>
We have:
-3x−8y−4−87z
Rewrite as:
3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
Hence, the equivalent expressions are 4x+ (y - 8y) + (2z-5z) +6 and 6x-3x-6x + (2y - 10y) + (4 - 8) + (z - 88z)
Read more about equivalent expressions at:
brainly.com/question/2972832
Answer: look below :)
Step-by-step explanation:
5 < 11 < 42 < 2015
5 is less than 11 is less than 42 is less than 2015
5/
1
< 11/
1
< 42/
1
< 2015/
1
The value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.
<h3>How to determine the dimensions?</h3>
The given parameters are:
Base = 5(x+3)
Height = 2(x+9)
Perimeter = 108
The perimeter of a rectangle is
P = 2 *(Base + Height)
So, we have:
2 *(5(x + 3) + 2(x + 9)) = 108
Divide both sides by 2
5(x + 3) + 2(x + 9) = 54
Open the brackets
5x + 15 + 2x + 18 = 54
Evaluate the like terms
7x = 21
Divide by 7
x = 3
Substitute x = 3 in Base = 5(x+3) and Height = 2(x+9)
Base = 5(3+3) = 30
Height = 2(3+9) = 24
Hence, the value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.
Read more about perimeter at:
brainly.com/question/24571594
#SPJ1