If a material contains three elements but not joined in a fixed proportion it is a

1 answer:

4 0

My answer -

<span> a molecule The clues are that it is elements, so that means atoms, and that it is in a fixed proportion like a molecular formula.

Happy to help you have a great day
</span>

You might be interested in

A long distance runner sees the finish line and accelerates at a rate in 1.2 m/s2 for

Nuetrik [128]

Answer: he did travel 15 meters.

Explanation:

We have the data:

Acceleration = a = 1.2 m/s^2

Time lapes = 3 seconds

Initial speed = 3.2 m/s.

Then we start writing the acceleration:

a(t) = 1.2 m/s^2

now for the velocity, we integrate over time:

v(t) = (1.2 m/s^2)*t + v0

with v0 = 3.2 m/s

v(t) = (1.2 m/s^2)*t + 3.2 m/s

For the position, we integrate again.

p(t) = (1/2)*(1.2 m/s^2)*t^2 + 3.2m/s*t + p0

Because we want to know the displacementin those 3 seconds ( p(3s) - p(0s)) we can use p0 = 0m

Then the displacement at t = 3s will be equal to p(3s).

p(3s) = (1/2)*(1.2 m/s^2)*(3s)^2 + 3.2m/s*3s = 15m

6 0

2 years ago

A sailboat is traveling across the ocean with a speed of 4 m/s when large gusts of wind pick up that starts to accelerate the sa

MatroZZZ [7]

Initial velocity, u = 4 m/s

acceleration due to gusts of wind = 3 m/s^2

time, t = 1 min = 60 s

Let distance travelled = S

From equation of motion,

$S = ut + \frac{1}{2} a {t}^{2} \\ \\ S = 4 \times 60 + \frac{1}{2} \times 3 \times {60}^{2} \\ \\ S = 240 + 5400 \\ \\ S = 5640 \: m$

Thus, the boat would have traveled 5640m after gusts picked up.

4 0

2 years ago

Read 2 more answers

5.0 Points The blue color of the sky is the result of

mina [271]

The blue color of the sky is the result of scattering. The answer is letter B. it is specifically called the Rayleigh scattering. This blue color is the result of the incoming rays of the Sun into the earth’s atmosphere. It has he lowest wavelength which as we all see is the blue spectrum of light.

7 0

2 years ago

What is the magnitude of the acceleration vector which causes a particle to move from velocity −5i−2j m/s to −6i+ 7j m/s in 8 se

shusha [124]

Answer:

Acceleration, $a=\dfrac{1}{8}(-i+9j)\ m/s^2$