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irinina [24]
3 years ago
15

A ball is thrown horizontally from the top of a building 22.3 m high. The ball strikes the ground at a point 127 m from the base

of the building. The acceleration of gravity is 9.8 m/s^2 . Find the time the ball is in motion. Answer in units of s.
Physics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

t = 2.13 s

Explanation:

given,

height of the building = 22.3 m

horizontal distance = 127 m

acceleration due to gravity = 9.8 m/s²

time for which ball is in motion = ?

using equation of motion

s = u t + \dfrac{1}{2}gt^2

initial velocity is zero

s = \dfrac{1}{2}gt^2

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 22.3}{9.8}}

       t = √4.551

        t = 2.13 s

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Answer:

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2 years ago
A thin hoop is hung on a wall, supported by a horizontal nail. The hoop's mass is M=2.0 kg and its radius is R=0.6 m. What is th
boyakko [2]

Answer:

Explanation:

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I = 0.72 kgm²

Period of a physical pendulum of small amplitude is given by

T = 2π √(I / Mgd)

Where,

T is the period in seconds

I is the moment of inertia in kgm²

I = 0.72 kgm²

M is the mass of the hoop

M = 2kg

g is the acceleration due to gravity

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d is the distance from rotational axis to center of of gravity

Therefore, d = r = 0.6m

Then, applying the formula

T = 2π √ (I / MgR)

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3 years ago
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Marrrta [24]

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A box falls out of a stationary helicopter hovering 135 m above the ground will take 5.25 seconds to reach the ground.

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