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pickupchik [31]
2 years ago
15

4cm cubed = ?m cubed

Physics
1 answer:
Neporo4naja [7]2 years ago
5 0

Answer:

{ \rm{1 \:  {cm}^{3} =  \frac{1}{100 {}^{3} }  \:  {m}^{3}  }} \\  \\  { \rm{4 \:  {cm}^{3}  =  \frac{4}{1000000}  \:  {m}^{3} }} \\  \\ { \boxed{ \rm{ = 0.000004 \:  {m}^{3} }}}

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A 26.2-kg dog is running northward at 3.02 m/s, while a 5.30-kg cat is running eastward at 2.74 m/s. Their 65.1-kg owner has the
REY [17]

Answer:

Angle with the +x axis is θ = 79.599degree

Then the velocity of owner = 1.235m/s

Explanation:

Given that the mass of dog is m1 =26.2 kg

velocity of dog is u1 = 3.02 m/s (north)

mass of cat is m2 = 5.3 kg

velocity is u2 = 2.74 m/s (east )

Mass of owner is M = 65.1 kg

Consider the east direction along +x axis andnorth along +y

momentum of dog is Py = m1 x u1

= 79.124 kg.m/s (j)

momentum of cat is Px = m2 x u2

= 14.522 kg.m/s (i)

Then the net magnitude of momentum is P = (Px2 + Py2)1/2

= 80.445

Angle with the +x axis is θ =tan-1(Py / Px ) = 79.599 degree

Then the velocity of owner is v = P / M = 1.235 m/s

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Which sound wave-object interaction is used by animals in echolocation?
tekilochka [14]
The answer is reflection
5 0
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3) show thal escape veloerty ve where symbols have their usual meaning?​
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Answer:

v = \sqrt{\frac{2GM}{r} }

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M - the mass of the object the escape should be made from

r - distance to the centre of that mass

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Hope this helps!
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