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pickupchik [31]
2 years ago
15

4cm cubed = ?m cubed

Physics
1 answer:
Neporo4naja [7]2 years ago
5 0

Answer:

{ \rm{1 \:  {cm}^{3} =  \frac{1}{100 {}^{3} }  \:  {m}^{3}  }} \\  \\  { \rm{4 \:  {cm}^{3}  =  \frac{4}{1000000}  \:  {m}^{3} }} \\  \\ { \boxed{ \rm{ = 0.000004 \:  {m}^{3} }}}

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A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark
Natali5045456 [20]

The total displacement of the toy car at the given positions is 0.

The given parameters;

  • <em>First displacement of the car, = 5 cm left</em>
  • <em>Second displacement of the car, = 8 cm right</em>
  • <em>Third displacement of the car, = 3 cm to the left</em>

The total displacement of the car is calculated as follows;

  • <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
  • <em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

\Delta x = - \ 5\ cm  \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

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2 years ago
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Iteru [2.4K]

Answer:

<h2>1. Friction is A. a force</h2>

<h2>2. An unbalanced force is B. When the object moves and accelerates</h2>
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O be useful in science, a hypothesis must be *
shepuryov [24]

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A rock is dropped from a vertical cliff. The rock takes 6.00 s to reach the ground below the cliff. What is the height of the cl
Lana71 [14]

Answer:

180 m

Explanation:

The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

h=\frac{1}{2}gt^2

where

g = 10 m/s^2 is the acceleration due to gravity

t = 6.00 s is the time of the fall

Substituting these data, we find the height of the cliff:

h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m

4 0
3 years ago
Calculate the average value of an AC signal with a peak amplitude of 10V and a frequency of 10 kHz.
Solnce55 [7]

Answer:

V(average)=6.37 V

Explanation:

Given Data

Peak Voltage=10V

Frequency=10 kHZ

To Find

Average Voltage

Solution

For this first we need to find Voltage peak to peak

So

Voltage (peak to peak)= 2× voltage peak

Voltage (peak to peak)= 2×10

Voltage (peak to peak)= 20 V

Now from Voltage (peak to peak) formula we can find the Average Voltage

So

Voltage (peak to peak)=π×V(average)

V(average)=Voltage (peak to peak)/π

V(average)=20/3.14

V(average)=6.37 V

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