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Firlakuza [10]
3 years ago
8

What could we call the grocery store? A. Linear motion B. Reference point C. Rotary

Physics
1 answer:
Roman55 [17]3 years ago
8 0

Reference point

Explanation:

I am not sure

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If you apply 150 newtons (N) of force to a solid brick wall for 5 seconds, but you do not move it, howmuch work have you done?A.
Lina20 [59]

Answer:

since there is no displacement, d = 0

Explanation:

hence work = f×d

= 150×0

= 0J

8 0
3 years ago
*Please help this is my final* If the car has a mass of 700 kg, how many newtons of forxe were used to accelerate it 30m/s/s
Vaselesa [24]

Answer:

21,000 N

Explanation:

You would use the formula F=ma

So you would do substitution...

F=700 kg(30 m/s/s)

F=21,000 N

6 0
3 years ago
2. A 2kg body attached to a spring undergoes a SHM of amplitude 0.4m and period
Rudik [331]

Answer:

a) 12.8 N

b) 3.2 m/s²

Explanation:

I'm guessing the period is 0.5π s.

Period of a spring in simple harmonic motion is:

T = 2π √(m/k)

Given T = 0.5π and m = 2 kg:

0.5π = 2π √(2/k)

0.25 = √(2/k)

0.0625 = 2/k

k = 32

The spring constant is 32 N/m, and the maximum displacement is 0.4 m.  The maximum force can be found with Hooke's law:

F = kx

F = (32 N/m) (0.4 m)

F = 12.8 N

The acceleration can be found with Newton's second law:

∑F = ma

kx = ma

(32 N/m) (0.2 m) = (2 kg) a

a = 3.2 m/s²

8 0
3 years ago
When is the universal theme of a story often revealed?
elena-14-01-66 [18.8K]
It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
7 0
3 years ago
Read 2 more answers
A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill
ozzi

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

                             S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

                            h = S²g/2Vx²                     (Since Vy = 0)

Substituting the values

                             h = 42² x 9.8/ (2 x 15²)

                                = 38.42 m

Hence, the height of the hill is, h = 38.42 m

4 0
4 years ago
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