What could we call the grocery store? A. Linear motion B. Reference point C. Rotary

Newton's Law of Cooling states that the rate of cooling of an object is proportional to the temperature difference between the o

Hoochie [10]

Answer:

$\frac{dy}{dt}=k(y_t-R)$

Explanation:

According to Newton’s law of cooling, the rate of loss of heat from a body and the difference in the temperature of the body and its surroundings are proportional to each other.

$\frac{dy}{dt}=k(y_t-R)$

Here, $y_t$ represents temperature at time t, R as the room temperature, t as the independent variable, y as the dependent variable.

3 0

4 years ago

This question is typical on some driver’s license exams: A car moving at 45 km/h skids 15 m with locked brakes. How far will the

sergiy2304 [10]

from kinematics equation if we know that final speed is ZERO and initial speed is given that due to constant deceleration the object will stop in some distance "d" and this distance can be calculated by kinematics

$v_f^2 - v_i^2 = 2 a d$

$0 - v^2 = 2(a)d$

here acceleration due to friction will be same at all different speed

so for 45 km/h speed the distance of stop is 15 m

while at other speed 112.5 km/h the distance will be unknown

now we will have

$0 - 45^2 = 2(a)15$

$0 - 112.5^2 = 2(a)d$

now divide above two equations

$\frac{45^2}{112.5^2} = \frac{15}{d}$

$d = 93.75 m$

So it will stop in distance 93.75 m

8 0

3 years ago

(PLEASE HELP! Will give Brainliest Answer)

soldi70 [24.7K]

Answer:

B

Explanation:

872 / 20 = 43

4 0

4 years ago

Determine the moment of the force at AAA about point PPP. Use a vector analysis and express the result in Cartesian vector form.

Dimas [21]

Answer:

τ = 0

Explanation:

At the moment it is defined

τ = F x r

In tete case they give us the strength and position in Cartesian form, so it is easier to solve the determinant

τ = $\left[\begin{array}{ccc}i&j&k\\F_{x}&F_{y}&F_{z}\\x&y&z\end{array}\right]$

Let's apply this expression to the exercise

a) P = (-6 i ^ -3j ^ -6 k ^) m

F = (-6 i ^ -3j ^ -6k ^) 103 N

τ = $\left[\begin{array}{ccc}i&j&k\\-6&-3&-6\\-6&-3&-6\end{array}\right]$

τ = i ^ (3 6 - 3 6) + j ^ (6 6 -6 6) + k ^ (6 3 - 3 6)

τ = 0

b) P = 24i ^ + 8j ^ + 9k ^

F = 24i + 8j + 9k

τ = i ^ (72-72) + j ^ (216-216) + k ^ (24 8 - 8 24)

τ = 0

c) P = -6i + 6j-4k

F = -6i + 6j-4k

τ = i ^ (24-24) + j ^ (- 24 + 24) + k ^ (-36 + 36)

τ = 0

.d) P = 24i-8j + 9k

Let's change the sign of strength

F = -24i + 8j-9k

Tae = (I j k 24 -8 9 -24 8 -9)

Tae = i ^ (72 -72) + j ^ (- 216 + 216) + k ^ (192-192)

Tae = 0

8 0

3 years ago

The rate of change of velocity or speed is known as acceleration. If a car increases it speed form 10 to 20m/s in 2 seconds, the

lisov135 [29]

Answer:

A) 5 m/s/s

Explanation:

Given the following data;

Initial velocity = 10m/s²

Final velocity = 20m/s²

Time, t = 2 seconds.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

$Acceleration, a = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation, we have;

$Acceleration, a = \frac{20 - 10}{2}$

$Acceleration, a = \frac{10}{2}$

Acceleration, a = 5m/s²

7 0

3 years ago