Answer:
a)
b)
Explanation:
L = inductance of the Inductor = 3.14 mH = 0.00314 H
C = capacitance of the capacitor = 5.08 x 10⁻⁶ F
a)
f = frequency = 55.7 Hz
Impedance is given as
b)
f = frequency = 11000 Hz
Impedance is given as
Answer:
The magnitude of the uniform magnetic field exerting this torque on the loop is 1.67 T
Explanation:
Given;
radius of the wire, r = 0.45 m
current on the loop, I = 2.4 A
angle of inclination, θ = 36⁰
torque on the coil, τ = 1.5 N.m
The torque on the coil is given by;
τ = NIBAsinθ
where;
B is the magnetic field
Area of the loop is given by;
A = πr² = π(0.45)² = 0.636 m
τ = NIBAsinθ
1.5 = (1 x 2.4 x 0.636 x sin36)B
1.5 = 0.8972B
B = 1.5 / 0.8972
B = 1.67 T
Therefore, the magnitude of the uniform magnetic field exerting this torque on the loop is 1.67 T
Answer:
option A is correct as 1 yard consist of 0.9144 meter which is less than one meter
Explanation:
from the above given statement option 1 is true
1 yard is equal to 0.9144 meter
while
1 mile is equal to 1.60934 km
1 foot is equal to 30.48 centimeter
1 inch is equal to 2.54 centimeter
therefore all these units [left one] are larger than their respective conversion [ right one unit]
therefore option A is correct as 1 yard consist of 0.9144 meter which is less than one meter
