Answer:
Use Fc centripetal force as positive and W the weight as negative
N = m v^2 / R + m g
v^2 = (N - m g) R / m
v^2 = (995 - 57 * 9.8) 42.7 / 57 = 327 m^2/s^2
v = 18.1 m/s
Note: N - m g is the net force producing the centripetal force
Answer:
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<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well.
That implies
option A is correct.</span>
Answer:
Decrease the distance between the two objects.
Explanation:
The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:
F = GM₁M₂ / r²
NOTE: G is the gravitational force constant.
From the equation:
F = GM₁M₂ / r²
We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.
Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.
Considering the question given above,
To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.
At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e 
).
The time of the ball in air is 3.2 s, so ascending time is 
.
Therefore from kinematic equation,
Substituting the values we get,
, Here v = 0 at top.
Now from equation,
, here h is the height .
So,
.
Thus, the ball reached at its maximum height of 12.48 m.
