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zimovet [89]
3 years ago
15

A 51.0-kg woman wearing high-heeled shoes is invited into a home in which the kitchen has vinyl floor covering. The heel on each

shoe is circular and has a radius of 0.400 cm. If the woman balances on one heel, what pressure does she exert on the floor?
Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

Pressure = 9.94 x 10⁶ Pascals

Explanation:

given data

mass = 51 kg

radius = 0.400 cm

solution

we know Pressure that is express as here

Pressure = total force on an area ÷ the area of the area   .................1

and

Force is the woman's weight so weight will be

Weight = mass × gravity  .................2

put here value

Weight = 51 × 9.8 m/s²

Weight = 499.8 Newtons

and

Area of a circle of bottom of the heel = (π) × (radius)²    ...................3

put here value

Area = (π) × (0.40 cm)²

Area = 0.502654 cm²

Area = 0.0000502654 m²

and

now we put value in equation 1 we get

Pressure = force ÷ area

Pressure = 499.8 ÷ 0.0000502654

Pressure = 9943221.381 N/m²

Pressure = 9.94 x 10⁶ Pascals

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A golf club hits a stationary 0.05kg golf ball with and average force of 5.0 x 10^3 newtons accelerating the ball at 44 meters p
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f=ma=\frac{m\times v}{t}

t=\frac{0.05 kg\times 44m/s}{5.0\times 10^3 N}=4.4\times 10^{-4} seconds

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Read 2 more answers
If a transmission line in a cold climate collects ice, the increased diameter tends to cause vortex formation in a passing wind.
AleksAgata [21]

Answer:

a) f_1=5.587Hz

b) f_{n+1}-f_n=5.587Hz

Explanation:

The frequency of the n^{th} harmonic of a vibrating string of length <em>L, </em>linear density \mu under a tension <em>T</em> is given by the formula:

f_n=\frac{n}{2L} \sqrt{\frac{T}{\mu}

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f_1=\frac{1}{2(347m)} \sqrt{\frac{65.4\times10^6N}{4.35kg/m}}=5.587Hz

b) The <em>frequency difference</em> between successive modes is the fundamental frequency, since:

f_{n+1}-f_n=\frac{n+1}{2L} \sqrt{\frac{T}{\mu}}-\frac{n}{2L} \sqrt{\frac{T}{\mu}}=(n+1-n)\frac{1}{2L} \sqrt{\frac{T}{\mu}}=\frac{n}{2L} \sqrt{\frac{T}{\mu}}=f_1=5.587Hz

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2 years ago
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