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Vera_Pavlovna [14]
3 years ago
13

A material that provides resistance to the flow of electric current is called a(an)

Physics
2 answers:
stira [4]3 years ago
8 0
An insulator is a material that provides resistance to the flow of electric current. Insulators include rubber, plastic, glass since they do not allow electricity to flow through them.
Troyanec [42]3 years ago
8 0

Answer: Insulator

Explanation: It doesnt allow electric currents through

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What is the state of matter that consists of a gas-like mixture of free electrons and nucle of atoms that have been stripped of
monitta
I think the answer is plasma which is a fourth state of matter.
5 0
4 years ago
What is evaporation? Condensation? Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
krok68 [10]

Answer:

Evaporation is the physical change in which a substance converts from its <u>liquid</u> state to its <u>gaseous</u> state. Condensation is the physical change in which a substance converts from its <u>gaseous</u> state to its <u>liquid</u> state.

Explanation:

Evaporation and condensation are opposite processes to each other. Evaporation changes a liquid to a gas and condensation is the reverse.

7 0
4 years ago
Relationship between voltage, resistance and current in a circuit
Lena [83]

Answer:

V = I×R

where -

V = potential difference across

I = current flowing in the circuit

R = Equivalent Resistance in the circuit

8 0
3 years ago
The string of a bow and arrow is pulled tight.
SOVA2 [1]

Answer:

elastic

Explanation:

8 0
3 years ago
A 221 g cart starts from rest and rolls in the right direction (positive) down an incline. The incline is at a height of 5 cm. A
Julli [10]

Answer:

1) p₀ = 0.219 kg m / s, p = 0, 2)  Δp = -0.219 kg m / s, 3) 100%

Explanation:

For the first part, which is speed just before the crash, we can use energy conservation

Initial. Highest point

            Em₀ = U = mg y

Final. Low point just before the crash

           Emf = K = ½ m v²

          Em₀ = Emf

          m g y = ½ m v²

           v = √ 2 g y

Let's calculate

           v = √ (2 9.8 0.05)

           v = 0.99 m / s

1) the moment before the crash is

           p₀ = m v

           p₀ = 0.221 0.99

           p₀ = 0.219 kg m / s

After the collision, the car's speed is zero, so its moment is zero.

           p = 0

2) change of momentum

           Δp = p - p₀

            Δp = 0- 0.219

            Δp = -0.219 kg m / s

3) the reason is

     Δp / p = 1

In percentage form it is 100%

3 0
4 years ago
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