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ArbitrLikvidat [17]
3 years ago
12

The mass of one atom would best be measured in this unit:

Physics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

mass of one atom is measured in the unit of 1 amu

Explanation:

As we know that the mass of one atom is very small and it is of order of 10^{-27}

here we know that 1 amu is defined as 1/12 part of mass of 1 atom of C-12 isotope

so here we will have

1 amu = 1.66 \times 10^{-27} kg

so here we can say that mass of one atom is measured in the unit of 1 amu

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Calculate the potential energy of a body of a mass 2kg held 4 meters above the ground if g=10m/s?​
Drupady [299]

Answer:

16000

Explanation:

Mass(m)=2Kg (1kg= 1ooo g then 2 kg=2000 g)

Velocity(v)= 4 meter

Acceleration due to gravity (g)=10m/s

We know that,

P.E= 1/2 mv^2

or, 1/2 × 2ooo × 4^2

or, 1/2×2000 ×16

or, 2000×8

Therefore= 16000

7 0
2 years ago
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Answer:

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Explanation:

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3 years ago
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A helicopter and a jet airplane must work against gravity in order to fly. Which one flys faster
Gre4nikov [31]
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3 0
4 years ago
6.For the following questions, use a periodic table and your atomic calculations to find the unknown information about each isot
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3 years ago
car 2 has a mass of 150 kg and moves westward towards car 3 at a velocity of 2.2 m/s. car 3 has a mass of 265 kg and moves eastw
sergejj [24]

Answer:

The force of car 3 on car 2 ≈ 1810.82 N

Explanation:

The equation for the change in momentum of the two cars are;

Conservation of linear momentum

150( 2.2 - v) = 265(1.5-v)

150 × 2.2 - 265×1.5 = (150+265)v

150 × 2.2 - 265×1.5 = -67.5 = 415×v

∴ v = -67.5/415 = -0.1627 m/s West = 0.1627 m/s East

The impulse of the net force is the amount of momentum change experienced given by the equation;

Impulse force = m \times  v_f - m \times  v_0

Where;

v_f = The final velocity

v_0 = The initial velocity

For the the 265 kg mass, we have;

v_f = 0.1627 m/s

v_0 = 1.5 m/s

Which gives the impulse a s F×Δt =  265×0.1627 - 265×1.5 = -354.38 kg·m/s

The change in kinetic energy of the collision = 1/2×265×(0.1627^2 - 1.5^2) =-294.62 J

Whereby the distance moved in one second is 0.1627 m, we have;

Work done = Force × Distance = Force × 0.1627 = 294.62

Force = 294.62/0.1627 = 1810.82 N.

8 0
3 years ago
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