<span>One everyday life experience that seems to support the geocentric model is the rising and setting of the Sun and Moon. The Moon rises and falls because it does revolve around the Earth and so it is easy to assume the same is true for the Sun.</span>
Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
Answer:
The potential energy stored in the spring is 0.018 J.
Explanation:
Given;
spring constant, k = 90 N/m
extension of the spring, x = 2 cm = 0.02 m
The potential energy stored in the spring is calculated as;
U = ¹/₂kx²
where;
U is the potential energy stored in the spring
Substitute the given values in the equation above;
U = ¹/₂ x 90 N/m x (0.02 m)²
U = 0.018 J
Therefore, the potential energy stored in the spring is 0.018 J.
A). No. A mirror doesn't separate light into its different wavelengths.
B). No. Light doesn't separate into its different wavelengths when it
goes, say, from glass into water.
C). No. When light goes through your glasses, it doesn't separate
into its different wavelengths.
D). Yes ! When sunlight shines into droplets of water in the atmosphere,
it comes out separated into its different wavelengths. When we see that
happening in the air in front of us, we call it a "rainbow".
Answer:
$84
Explanation:
The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.
The heater consumed by the heater is 1200 kWh.
For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:
Electric input to heat pump = 1200 / 2.4 = 500 kWh
That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh
The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh
Money saved = $0.12/kWh * 700 kWh = $84
