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Leno4ka [110]
3 years ago
9

An air mass that forms over Arizona and New Mexico will be?

Physics
1 answer:
vlada-n [284]3 years ago
5 0
Continental Tropical Air Mass. Your welcome matey
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When you walk at an average speed (constant speed, no acceleration) of 20.7 m/s in 75.8 sec you will cover a distance of______?
insens350 [35]

Answer:

You will cover a distance of 1569.06 metres. Or you could round down to 1,569m.

Explanation:

20.7*75.8=1563.06

7 0
3 years ago
In what different ways can be sound heard​
Mekhanik [1.2K]
The question is a bit ambiguous, but sound can be heard at different frequencies and amplitudes.
5 0
2 years ago
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The maximum speed of a mass m on an oscillating spring is vmax . what is the speed of the mass at the instant when the kinetic a
umka21 [38]
Let
A =  the amplitude of vibration
k =  the spring constant
m =  the mass of the object

The displacement at time, t, is of the form
x(t) = A cos(ωt)
where
ω =  the circular frequency.

The velocity is
v(t) = -ωA sin(ωt)

The maximum velocity occurs when the sin function is either 1 or -1.
Therefore
v_{max} = \omega A
Therefore
v(t) = -V_{max} sin(\omega t)

The KE (kinetic energy) is given by
KE = \frac{m}{2}v^{2} = \frac{m}{2} V_{max}^{2} sin^{2} (\omega t)

The PE (potential energy) is given by
PE = \frac{k}{2} x^{2} = \frac{k}{2} A^{2} cos^{2} (\omega t)

When the KE and PE are equal, then
v^{2} = \frac{k}{m} A^{2} cos^{2} (\omega t)

For the oscillating spring,
\omega ^{2} =  \frac{k}{m} \\ V_{max} = \omega A =  \sqrt{ \frac{k}{m} } A
Therefore
v^{2} =  \frac{k}{m}  \frac{m}{k} V_{max}^{2} cos^{2} ( \sqrt{ \frac{k}{m} t} ) \\ v = V_{max}  \,cos( \sqrt{ \frac{k}{m} t} )

Answer: v(t) = V_{max} cos( \sqrt{ \frac{k}{m} t} )

3 0
4 years ago
Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni
sweet-ann [11.9K]

Answer:

d) 1/4 F

Explanation:

The magnitude of electrostatic force between stationary charges is described by Coulomb's law. This law states that this force is proportional to the magnitudes of the charges:

F\propto q_1q_2

When each of the spheres has lost half its initial charge, we have:

q_1'=\frac{q_1}{2}\\q_2'=\frac{q_2}{2}

So, the new electrostatic force is:

F'\propto q_1'q_2'\\F'\propto \frac{q_1}{2}\frac{q_2}{2}\\F'\propto \frac{q_1q_2}{4}\\F'\propto\frac{1}{4}F

5 0
3 years ago
How many watts equal to 1 kilowatt
ankoles [38]
Your answer is 1000 watts.
            Hope this helps!
5 0
3 years ago
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