What is the nearest 1/4 inch to 1 1/2 inches?

An engineer is building a bridge that should be able to hold a maximum weight of 1 ton. He builds a model of the bridge that is

MrRissso [65]

Answer:

First blank- 32000 ounces

Second blank- 2000 pounds

Yes the bridge can hold 1 ton.

Step-by-step explanation:

The ratio of the scale of the model to the real bridge = 1:4

The test model shows the model can take 8000 ounces

The real bridge will therefore take 8000 x 4 = 32000 ounces

16 ounces = 1 pound

32000 ounces = x pounds

==> = 32000/16 = 2000 pounds

2000 pounds = 1 ton

therefore the bridge holds 1 ton

6 0

2 years ago

Read 2 more answers

The table below shows the illuminated percentage of the moon on a lunar cycle of 28 days. The relationship can be described usin

natulia [17]

Answer:

The amplitude of the function is 48

The period of the function is 28

The graph has a vertical shift of 48 units.

Step-by-step explanation:

just took the quiz

7 0

3 years ago

Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.

gladu [14]

Answer:

Vertical asymptote: $x=3$

Horizontal asymptote: $f(x) =2$

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

$f (x) = -\dfrac{1 }{ x-3} +2$

One root, $x = 3.5$

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

Roots of f(x) means the value of x where f(x) = 0

$0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5$

One root, $x = 3.5$

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) $\rightarrow \infty$

For all, other values of $x$ , $f(x)$ is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is $\frac{1}{x-3}$ .

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) $\rightarrow \infty$ .

$-\dfrac{1 }{ x-3} +2 \rightarrow \infty$

It is possible only when

$x-3=0\\\Rightarrow x=3$

$\therefore$ vertical asymptote: $x=3$

Horizontal Asymptote is the value of f(x) , where value of x $\rightarrow \infty$ .

$x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2$

$\therefore$ Horizontal asymptote: $f(x) =2$

Please refer to the graph of given function as shown in the attached image.

5 0

3 years ago

It takes Manisha 38 seconds to climb up the stairs of her house. If she spends 504 seconds doing this, how many minutes has she

Mrac [35]

Answer:

Manisha spent 8 minutes and 24 seconds in a week climibing the stairs of her house.

Step-by-step explanation: (totally my work, not copied)

Convert seconds to minutes.

60x8=480

60x9=540

so, 8 minutes

Find the remaining seconds.

504-480=24

Add remaining seconds to minutes

24sec+8min=8min24sec

So hence, your answer is 8 Minutes and 24 Seconds

Manisha spent 8 minutes and 24 seconds in a week climbing the stair of her house.

Thanks!

Mark me brainliest!

~ $FieryAnswererGT$ ~

5 0

2 years ago

What is the slope of a line that is parallel to the line -6y=8x-4?

lesya692 [45]

Answer:

-4

3

Step-by-step explanation:

-6y=8x-4

0=8x+6y-4---(i)

slope (m1)=-coefficient of x

coefficient of y

=-8

6

= -4

3

As the lines are parallel,

m1=m2

so,

The slope of line parallel to the line having equation -6y=8x-4 is -4

3

5 0

3 years ago