Answer:
0.25 feet per minute
Step-by-step explanation:
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.


Since base diameter = Height of the Cone
Radius of the Cone = h/2
Therefore,


Therefore: 
We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute
Answer:
74.86% probability that a component is at least 12 centimeters long.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Variance is 9.
The standard deviation is the square root of the variance.
So

Calculate the probability that a component is at least 12 centimeters long.
This is 1 subtracted by the pvalue of Z when X = 12. So



has a pvalue of 0.2514.
1-0.2514 = 0.7486
74.86% probability that a component is at least 12 centimeters long.
I believe C. Because it provides a more meaningful explanation
Answer: ok so Let's simplify step-by-step.
r−3q+5p−(−4r−3q−8p)
Distribute the Negative Sign:
=r−3q+5p+−1(−4r−3q−8p)
=r+−3q+5p+−1(−4r)+−1(−3q)+−1(−8p)
=r+−3q+5p+4r+3q+8p
Combine Like Terms:
=r+−3q+5p+4r+3q+8p
=(5p+8p)+(−3q+3q)+(r+4r)
=13p+5r
Step-by-step explanation:
We are given a function of the bouncing of the ball expressed as f(n) = 9(0.7)n in which n is an integer as the number of times the ball has dropped. 9 represents the initial height of the ball and 0.7 is the percent of which the height is reserved