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masha68 [24]
3 years ago
6

Convert 0.5 (repeating) into a fraction

Mathematics
2 answers:
NARA [144]3 years ago
5 0
Well 0.5 is 1/2... hope this helps
Papessa [141]3 years ago
3 0
I believe it would be 5/9
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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?
astraxan [27]
ANSWER


The value of the expression is
- 1


EXPLANATION

Method 1: Rewrite as product of
{i}^{2}


The expression given to us is,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}


We use the fact that
{i}^{2}  =  - 1
to simplify the above expression.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


This implies,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


We substitute to obtain,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


Method 2: Use indices to solve.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{0 + 1 + 2 + 3 + 4}



This implies that,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{10}




{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (  {{i}^{2}} )^{5}


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (   - 1 )^{5}   =  - 1


8 0
3 years ago
Read 2 more answers
Given: F(x)=x+2 and G(x)=3x+5 <br> (F - G) (x) = ?<br><br><br> 4<br> -3x-3<br> -3x-3
lakkis [162]
What’s the x your trying to find
4 0
4 years ago
For the function defined by y = 1/x4, y varies inversely as what quantity
gregori [183]

ANSWER

y varies inversely as x exponent 4.

EXPLANATION

The inverse variation equation is given as:

y =  \frac{1}{ {x}^{4} }

We can see that there is an inverse relation between the quantity y and x.

If the it were y =  \frac{1}{ {x}^2 }, we say y varies inversely as the square of x.

Hence for the given relation,the precise definition is that, y varies inversely as x exponent 4.

6 0
3 years ago
determine the number of outcome and decide whether the event is simple or not.A computer is used to randomly select a number bet
ollegr [7]
Based on your answer where ask to determined the number of outcome and decide whether the event is simple or not.
-So in event A is 4000 and a sample space
-So event B is 500 its just a number of outcome
6 0
4 years ago
21 POINTS!! Thank you so much!! There’s also things on my page worth lots points points as well! So if you could help with those
Art [367]

Answer:

Second one

third one

fifth one

last one

Step-by-step explanation:

Based on the x intercepts we can write

a(x+1)(x-5)

where a is some constant

solve for a by plugging in some coordinates

let's plug in (1,-8)

-8=a(1+1)(1-5)

-8= -8a

a=1

therefore the quadratic is (x+1)(x-5)

expand this

x²-4x-5

To find out where something is decreasing/increasing it's easiest to take the first derivative

x²-4x-5= 2x-4

set this equal to 0

2x-4=0

2x=4

x=2

Which means that our two intervals are

(-∞,2)U(2,∞)

plug in any values in the intervals to see whether or not the function is increasing/decreation

Let's plug in 0 for (-∞,2)

2(0)-4

-4

It's negative so it's decreasing on this interval

DO the same thing with the other one

let's plug in x=3

2(3)-4

2

this is positive so it's increasing on this interval

Go back to the critical value of x=2 and plug this into the equation to find the max/min

(2+1)(x-5)= -9

This is a minimum because the cofeccient for the degree is positive

For the limit one notice that we have a positive, even degree which means the end behavior is positive, positive

what this means is as x approaches negative infinity it's infinity

and as x approaches infinity it's infinity

6 0
3 years ago
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