Answer:
Tony can buy three games with his savings over two months and Alice can buy six concert tickets.
Step-by-step explanation:
Over two months, Tony has watched a total of 53.6 hours of television (35.4 + 18.2). If he save $2.50 for each hour, we can multiply his total hours by the amount per hour, or 53.6 x 2.50 = $134.00. Since each game that Tony wants to buy costs $35.75, we need to divide his total savings by the cost of each game, or 134/35.75 = 3.75. Since Tony can't buy a portion of the game, the most amount of games he can buy is 3. Alice watched a total of 48.4 hours of television (21.8 + 26.6). If she also saves $2.50 per hour, then her total savings is 2.50 x 48.4 = $121.00. Since her concert tickets are $17.50 a piece, we divide her total savings: 121/17.50 = 6.9. Alice can also not buy a partial ticket, so the total amount she can buy is 6.
There are no real solutions
I'm glad to hear that, but where is the math problem?
Answer
The steel ball will be caught up in between the mercury and water medium.
Step-by-step explanation:
- Mercury with a density of 13546 kg/m^3
- water with a density of 1000 kg/m^3
- Steel with a density of 8050 kg/m^3
From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.
The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.
Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
