Answer:
CD= 15.03
Step-by-step explanation:
x1=7, x2= -8
y1=-4, y2=-5
distance CD= √(x2- x1) 2+ (y2-y1)2
= √( -8-7)2 + [-5-(-4)]2
= √(15)2+ (-5+4)2
= √225+ (1)2
= √225+1
= √226
= 15.03
We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
Answer: Mrs.Buller collects a 500-ml sample of seawater for her chemistry class, and it has 1.94% of chlorine, we have to determine the amount of chlorine in the sample:
Therefore the chlorine content in 500ml of water is 9.7ml.
Answer:
Step-by-step explanation:
slope of -2 means the slope is -2/1
from (3, - 8) you can find the y intercept by going backwords until x = 0
(2,-6)
(1,-4)
(0,-2)
so the y intercept is -2
y = -2x - 2
