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P(z ≤ 0. 82) or p-value corresponding to z ≤ 0. 82 comes to be approximately 80%.
<h3>What is a z-score?</h3>Z-score indicates how much a given value differs from the standard deviation.
Where = mean
=standard deviation
P(z ≤ 0. 82) means the p-value corresponding to z≤ 0. 82.
From the standard normal table
P(z ≤ 0. 82) ≈80%.
Hence, P(z ≤ 0. 82) or p-value corresponding to z ≤ 0. 82 comes to be approximately 80%.
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