Answer:
H. 13.5 in²
Step-by-step explanation:



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Solve the inequality , find the max possible value for the variable.
3t + 1 < t + 12
2t < 11
t < 5.5
t_max = 5.5
For the second question just solve as two separate inequalities
4 +2 < x <= 7 + 2
6 <x <= 9
x in ]6, 9]
The area of the polygon is 52.5cm^2.
Area of triangle + Area of rectangle
(b)(h)/2 + (b)(h)
(5)(5)/2 + (8)(5)
25/2 + 40
12.5 + 40
=52.5 centimeters squared