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Leni [432]
3 years ago
7

A toy uses a spring to shoot an arrow with a suction cup on the end. The toy shoots a 34.2 g arrow and gives it a speed of 5.50

m/s. If the efficiency of the toy is 69.0%, how much elastic potential energy was stored in the spring? Show all your work.
Physics
1 answer:
Jet001 [13]3 years ago
6 0

Explanation:

When spring is used to shoot an arrow, the Elastic Potential Energy is converted into Kinetic Energy.

The efficiency of Spring Toy = 69%

<u>According to Conservation of Energy</u> :

P. E. = K. E.

NOW,

69% of P. E. = m * v^2 / 2

P.E. =  \frac{0.0342 \times 5.5 \times 5.5}{2 \times 0.69}  = 0.75J

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Licemer1 [7]

Answer:

v=\frac{2K}{RqB}

m=\frac{(RqB)^2}{2K}

Explanation:

The formula for kinetic energy <em>K</em> of a particle of mass <em>m</em> moving at velocity <em>v</em> is K=\frac{mv^2}{2} and the formula for the Lorentz force <em>F</em> experimented by a particle of charge <em>q </em>and velocity <em>v</em> under a magnetic field <em>B</em> is (asuming <em>v</em> and <em>B</em> are perpendicular) F=qvB.

Since the particle would be moving in circles, this force would be a centripetal force given by F_{cp}=ma_{cp}=\frac{mv^2}{R}, where <em>R</em> is the radius of the trajectory.

Then we have (<em>q, K, R</em> and <em>B</em> would be what we know):

F=F_{cp}

qvB=\frac{mv^2}{R}=\frac{2K}{R}

v=\frac{2K}{RqB}

And:

m=\frac{2K}{v^2}=\frac{2K(RqB)^2}{(2K)^2}=\frac{(RqB)^2}{2K}

7 0
4 years ago
How many units measure one wavelength?<br><br><br> a<br> 16<br> b<br> 8<br> c<br> 2<br> d<br> 4
pochemuha
B it makes more sense
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Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artifici
wariber [46]

Answer:

Hi myself Shrushtee.

Explanation:

Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artificial gravity, human growth is stunted and biological functions break down. An effective way to create artificial gravity is through the use of a rotating enclosed cylinder, as shown in the figure. Humans walk on the inside edge of the cylinder, which is sufficiently large (diameter of 2235 meters) that its curvature is not readably noticeable to the inhabitants. (The space station in the figure is not drawn to the scale of the human.) Once the space station is rotating at the necessary speed, how many minutes would it take the space station to make one revolution?

The distance traveled by the man in one revolution is simply the circumference of the space station, C = 2p R. From this result, you should be able to deduce the time it takes for the space station to sweep out a complete revolution.

<h2><em><u>P</u></em><em><u>lease</u></em><em><u> mark</u></em><em><u> me</u></em><em><u> as</u></em><em><u> brainleist</u></em></h2>
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3 years ago
Does a perfectly elastic colission conserve momentum and impulse
Degger [83]

Answer:

A perfectly elastic collision conserves momentum and kinetic energy..

5 0
3 years ago
At one point in space, the electric potential energy of a 15 nC charge is 42 μJ . Part A) What is the electric potential at this
Anastasy [175]

Answer:

Part A:

\rm 2.8\times 10^3\ Volts.

Part B:

\rm 5.6\times 10^{-5}\ J.

Explanation:

<u> Part A:</u>

  • Potential energy of charge at the given point, \rm U=42\ \mu J=42\times 10^{-6}\ J.
  • Charge, \rm q=15\ nC = 15\times 10^{-9}\ C.

The potential energy at a point due to a charge is defined as

\rm U=qV.

<em>where</em>,

V = electric potential at that point.

Therefore,

\rm V=\dfrac{U}{q}=\dfrac{42\times 10^{-6}}{15\times 10^{-9}}=2.8\times 10^3\ Volts.

<u>Part B:</u>

Now, if the charge at that point is replaced with \rm q_1 = 20\ nC = 20\times 10^{-9}\ C., then the electric potential energy at that point is given by

\rm U=q_1V = 20\times 10^{-9}\times 2.8\times 10^3=5.6\times 10^{-5}\ J.

5 0
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