Answer:
40
Step-by-step explanation:
A = base x height
8 is base
5 is height (the height has to be perpendicular to the base. That's what the little square denotes. Along with the angle being 90°.
A = 8 x 5
A = 40
Answer:
You can see the graph in the attached file.
Step-by-step explanation:
You need to propouse values of x, and substitue into the equation to get the corresponding value of y. In other words you need to evaluate the function for each value of x. With those values you can build the table.
For example choose the value x = 0, then you can calculate the value of y:


f(0) = 6
Then when x = 0, y = 6
The coordinates for the graph (x, y) = (0, 6)
For the table choose different values, include: zero, negative and positive numbers.
x y
x = f(x)=
-20 -15330794
-15 -3582444
-10 -456694
-5 -12794
-1 2
0 6
1 4
5 17456
10 535306
15 3984306
20 16605206
Review the attached excel file, there you will see the table and how to do the calculations in the cell.
Once you have the values in the chart, select the data. Then from the bar choose insert and then select the xy scatter.
Also you can see the graph in the file.
Answer:
100;200
There are 200 total flips and to find probability we would have to divide it by two. Doing so, should give you something like this 100;200.
Answer:
The equation is
15x = 610
Step-by-step explanation:
A dime is 10 cents while a nickel is 5 cents
$6.10 is same as 610 cents
Let the number of dimes and number of nickels be x
10x + 5x = 610
15x = 610
Answer:
Step-by-step explanation:
The right statistical procedure is by applying a hypothesis test that uses a single mean. Here, if we are to talk about comparison, it should be between the mean IQ of the students in the class and the national average IQ. The class is not for a comparison between two population means because it is viewed as the sample of the population. That is to say, the required task is to determine if the sample mean is greater than the population mean. We can conclude that this obeys a hypothesis test rather than a confidence interval.